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3 years ago

What were three of tycho brahe’s reasons for believing his model had to be right??

2 answers:

3 0

1. He observed a super nova which disappeared after 18 months.

2. He observed a comet which proved that not everything is non-changing and not everything is a circular motion.

3. He measured the movement of planets and stars, couldn't find he parallax, conclusion: the earth is at the center of the universe un-moving.

Hope this helps!

lord [1]3 years ago

3 0

1. He observed a super nova which disappeared after 18 months.

2. He observed a comet which proved that not everything is non-changing and not everything is a circular motion.

3. He measured the movement of planets and stars, couldn't find he parallax, conclusion: the earth is at the center of the universe un-moving.

Explanation:

Tycho Brahe produced a prodigious volume of estimations and observations, but he didn't fabricate or hypothesize any particular model and didn't try to

Danish astronomer Tycho/Tyge Brahe (1546-1601) is immensely important for two reasons: Observing and holding the (rough) distance to a Supernova, thereby revealing that the atmosphere was not a God-given stable sphere, but a dynamic system.

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What happens to the strength of the magnetic field as you come closer to the current carrying wire?

lina2011 [118]

Electric energy is carried by current, which is the flow of electrons, which are the negatively charged sub-particles of atoms. This transfer of electrons from one place to another powers our lights, phones, appliances and many other things we use every day. Another interesting phenomenon of flowing current is that it produces its own magnetic field. Electricity and magnetism are very closely linked in that all closed loop currents create their own magnetic fields, and magnetic fields acting upon closed loop circuits can produce current or even change current diction.

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3 years ago

A person throws a stone from the corner edge of a building. The stone's initial velocity is 28.0 m/s directed at 43.0° above the

Naya [18.7K]

The stone's acceleration, velocity, and position vectors at time $t$ are

$\mathbf a(t)=-g\,\mathbf j$

$\mathbf v(t)=v_{i,x}\,\mathbf i+\left(v_{i,y}-gt\right)\,\mathbf j$

$\mathbf r(t)=v_{i,x}t\,\mathbf i+\left(y_i+v_{i,y}t-\dfrac g2t^2\right)\,\mathbf j$

where

$g=9.80\dfrac{\rm m}{\mathrm s^2}$

$v_{i,x}=\left(28.0\dfrac{\rm m}{\rm s}\right)\cos43.0^\circ\approx20.478\dfrac{\rm m}{\rm s}$

$v_{i,y}=\left(28.0\dfrac{\rm m}{\rm s}\right)\sin43.0^\circ\approx19.096\dfrac{\rm m}{\rm s}$

and $y_i$ is the height of the building and initial height of the rock.

(a) After 6.1 s, the stone has a height of 5 m. Set the vertical component $(\mathbf j)$ of the position vector to 5 m and solve for $y_i$ :

$5\,\mathrm m=y_i+\left(19.096\dfrac{\rm m}{\rm s}\right)(6.1\,\mathrm s)-\dfrac12\left(9.80\dfrac{\rm m}{\mathrm s^2}\right)(6.1\,\mathrm s)^2$

$\implies\boxed{y_i\approx70.8\,\mathrm m}$

(b) Evaluate the horizontal component $(\mathbf i)$ of the position vector when $t=6.1\,\mathrm s$ :

$\left(20.478\dfrac{\rm m}{\rm s}\right)(6.1\,\mathrm s)\approx\boxed{124.92\,\mathrm m}$

(c) The rock's velocity vector has a constant horizontal component, so that

$v_{f,x}=v_{i,x}\approx20.478\dfrac{\rm m}{\rm s}$

where $v_{f,x}$

For the vertical component, recall the formula,

${v_{f,y}}^2-{v_{i,y}}^2=2a\Delta y$

where $v_{i,y}$ and $v_{f,y}$ are the initial and final velocities, $a$ is the acceleration, and $\Delta y$ is the change in height.

When the rock hits the ground, it will have height $y_f=0$ . It's thrown from a height of $y_i$ , so $\Delta y=-y_i$ . The rock is effectively in freefall, so $a=-g$ . Solve for $v_{f,y}$ :

${v_{f,y}}^2-\left(19.096\dfrac{\rm m}{\rm s}\right)^2=2(-g)(-124.92\,\mathrm m)$

$\implies v_{f,y}\approx-53.039\dfrac{\rm m}{\rm s}$

(where we took the negative square root because we know that $v_{f,y}$ points in the downward direction)

So at the moment the rock hits the ground, its velocity vector is

$\mathbf v_f=\left(20.478\dfrac{\rm m}{\rm s}\right)\,\mathbf i+\left(-53.039\dfrac{\rm m}{\rm s}\right)\,\mathbf j$

which has a magnitude of

$\|\mathbf v_f\|=\sqrt{\left(20.478\dfrac{\rm m}{\rm s}\right)^2+\left(-53.039\dfrac{\rm m}{\rm s}\right)^2}\approx\boxed{56.855\dfrac{\rm m}{\rm s}}$

(d) The acceleration vector stays constant throughout, so

$\mathbf a(t)=\boxed{-g\,\mathbf j}$

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2 years ago

If a baseball's velocity is increased to four times its original velocity, by what factor does its kinetic energy increase

jeyben [28]

Answer:

16 times

Explanation:

Original

KE(i) = 1/2mv²

After increasing

KE(f) = 1/2m(4v)²

KE(f) = 8mv²

KE(f)/KE(i) = 8 x 2 = 16

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2 years ago

What instrument is used to measure volume by displacement

kicyunya [14]

Volumes of liquids such as water can be readily measured in a graduated cylinder.

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3 years ago

The height of the Empire State Building is 318.00 meters. If a stone is dropped from the top of the building, what is the stone'

Svetlanka [38]

Answer:

Explanation:

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2 years ago