The glider collides elastically an another glider at rest, in this case we have the coservation of quantity of movement
m1 v1 + m2 v2 = m1V1 + m2 V2
v is the velocity before the shock, V the velocity after the shock
m1=0.22
v1=0.60m/s
m2=0.44
V1=-0.20m/s
remark that <span>0.44 kg glider is initially at rest, so v2= 0
the equation above can be written </span><span>m1 v1 = m1V1 + m2 V2 ( because v2=0 at rest)
</span><span>m1 v1 = m1V1 + m2 V2 implies V2= (m1v1 -m1V1) / m2
</span>
V2=0.22x0.60 -0.22x (-0.20) ] / 0.44= 0.4m/s
Answer:
Uniform velocity is scalar , while variable velocity is vector
Explanation: Uniform velocity and variable velocity is that a body moving with uniform velocity has zero acceleration, while a body that is moving with variable velocity has some acceleration. Uniform velocity is the vector quantity while non-uniform or variable velocity is a scalar quantity
Answer: 0m/s²
Explanation:
Since the forces acting along the plane are frictional force(Ff) and moving force(Fm), we will take the sum of the forces along the plane
According newton's law of motion
Summation of forces along the plane = mass × acceleration
Frictional force is always acting upwards the plane since the body will always tends to slide downwards on an inclined plane and the moving acts down the plane
Ff = nR where
n is coefficient of friction = tan(theta)
R is normal reaction = Wcos(theta)
Fm = Wsin(theta)
Substituting in the formula of newton's first law we have;
Fm-Ff = ma
Wsin(theta) - nR = ma
Wsin(theta) - n(Wcos(theta)) = ma... 1
Given
W = 562N, theta = 30°, n = tan30°, m = 56.2kg
Substituting in eqn 1,
562sin30° - tan30°(562cos30°) = 56.2a
281 - 281 = 56.2a
0 = 56.2a
a = 0m/s²
This shows that the trunk is not accelerating
Answer:
the sun's heat affects humidity of how warm the air feels to us.
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