Michael has a substance that he puts in Container 1. The substance has a volume of 5 cubic meters. He then puts the substance in
1 answer:
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Answer:
The final equilibrium T_{f} = 25.7[°C]
Explanation:
In order to solve this problem we must have a clear concept of heat transfer. Heat transfer is defined as the transmission of heat from one body that is at a higher temperature to another at a lower temperature.
That is to say for this case the heat is transferred from the iron to the water, the temperature of the water will increase, while the temperature of the iron will decrease. At the end of the process a thermal balance is found, i.e. the temperature of iron and water will be equal.
The temperature of thermal equilibrium will be T_f.
The heat absorbed by water will be equal to the heat rejected by Iron.
Heat transfer can be found by means of the following equation.
where:
Qiron = Iron heat transfer [kJ]
m = iron mass = 200 [g] = 0.2 [kg]
T_i = Initial temperature of the iron = 300 [°C]
T_f = final temperature [°C]
Cp_iron = 437 [J/kg*°C]
Cp_water = 4200 [J/kg*°C]
Answer:
Lets take mass of A = m
Mass of B = m
Lets take spring constant = K
Displacement of mass A = x
Displacement of mass B= x'
Given that
x ' > x
a)
We know that time period of spring mass system given as
Time does not depends on the displacement.
So time will be same for both.
b)
We know that acceleration given as
a= ω² .x
ω=natural frequency ( ω² = m K)
Here x ' > x
So Acceleration of mass B is greater than mass A.
c)
Velocity at equilibrium position
V= ω .x
Here x ' > x
So velocity of mass B is greater than mass A.
d)
As we know that at equilibrium point acceleration of the mass is zero.So both the mass have same acceleration and the value of this acceleration will be zero m/s².