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hoa [83]
3 years ago
13

You need to know the height of a tower, but darkness obscures the ceiling. You note that a pendulum extending from the ceiling a

lmost touches the floor and that its period is 15 s. The acceleration of gravity is 9.81 m/s2 .
How tall is the tower? Answer in units of m
Physics
1 answer:
Sonja [21]3 years ago
6 0

Answer:

L=55.9m

Explanation:

The equation for the period of a simple pendulum is:

T=2\pi\sqrt{\frac{L}{g}}

In our case what we know is the period and the acceleration of gravity, and we need to know the length of the pendulum, so we can write:

L=(\frac{T}{2\pi})^2g

Which for our values is:

L=(\frac{15s}{2\pi})^2(9.81m/s^2)=55.9m

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How much force is required to accelerate a 0.10 gram mosquito at 20m/?
EastWind [94]

Answer:  0.002 newtons

===================================================

Work Shown:

I'm assuming you meant to write "at 20 m/s^2" at the end. If so, then,

0.10 grams = 0.10/1000 = 0.0001 kg

m = 0.0001 kg = mass

a = 20 m/s^2 = acceleration

F = ma .... newton's second law

F = 0.0001*20

F = 0.002

The force required is 0.002 newtons

8 0
3 years ago
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A tennis ball is tossed upwards into the air with an initial velocity of +5m/s, how much time does it take for the tennis ball t
Sever21 [200]
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3 0
2 years ago
A 55 kilogram person jumps off a cliff and hits the water 5.8 seconds later, how high is the cliff above the water?
ElenaW [278]
R=ut+gt^2/2
r- displacement (height to find)
u - initial speed (zero)
t - time taken

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8 0
3 years ago
A ball having mass 2 kg is connected by a string of length 2 m to a pivot point and held in place in a vertical position. A cons
Virty [35]

Complete Question

A ball having mass 2 kg is connected by a string of length 2 m to a pivot point and held in place in a vertical position. A constant wind force of magnitude 13.2 N blows from left to right. Pivot Pivot F F (a) (b) H m m L L If the mass is released from the vertical position, what maximum height above its initial position will it attain? Assume that the string does not break in the process. The acceleration of gravity is 9.8 m/s 2 . Answer in units of m.What will be the equilibrium height of the mass?

Answer:

H_m=1.65m

H_E=1.16307m

Explanation:

From the question we are told that

Mass of ball M=2kg

Length of string L= 2m

Wind force F=13.2N

Generally the equation for \angle \theta is mathematically given as

tan\theta=\frac{F}{mg}

\theta=tan^-^1\frac{F}{mg}

\theta=tan^-^1\frac{13.2}{2*2}

\theta=73.14\textdegree

Max angle =2*\theta= 2*73.14=>146.28\textdegree

Generally the equation for max Height H_m is mathematically given as

H_m=L(1-cos146.28)

H_m=0.9(1+0.8318)

H_m=1.65m

Generally the equation for Equilibrium Height H_E is mathematically given as

H_E=L(1-cos73.14)

H_E=0.9(1+0.2923)

H_E=1.16307m

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2 years ago
A train travels from the bottom of a hill to the top of a hill, its moves slower by the time it reaches the top is an example of
Neko [114]
The answer is letter C. <span>A train travels from the bottom of a hill to the top of a hill, its moves slower by the time it reaches the top is an example of negative acceleration.

In physics, acceleration can be described as an objects change of velocity. When an object gains velocity, it is positive acceleration, and negative acceleration for the opposite.

</span>

Thank you for posting your question. I hope you found what you were after. Please feel free to ask me more.

<span> </span>

5 0
2 years ago
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