Answer: 0.002 newtons
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Work Shown:
I'm assuming you meant to write "at 20 m/s^2" at the end. If so, then,
0.10 grams = 0.10/1000 = 0.0001 kg
m = 0.0001 kg = mass
a = 20 m/s^2 = acceleration
F = ma .... newton's second law
F = 0.0001*20
F = 0.002
The force required is 0.002 newtons
R=ut+gt^2/2
r- displacement (height to find)
u - initial speed (zero)
t - time taken
r=0*5.8 + 10*5.8^2 /2 = 168.2 meters
Complete Question
A ball having mass 2 kg is connected by a string of length 2 m to a pivot point and held in place in a vertical position. A constant wind force of magnitude 13.2 N blows from left to right. Pivot Pivot F F (a) (b) H m m L L If the mass is released from the vertical position, what maximum height above its initial position will it attain? Assume that the string does not break in the process. The acceleration of gravity is 9.8 m/s 2 . Answer in units of m.What will be the equilibrium height of the mass?
Answer:


Explanation:
From the question we are told that
Mass of ball 
Length of string 
Wind force 
Generally the equation for
is mathematically given as




Max angle =
Generally the equation for max Height
is mathematically given as



Generally the equation for Equilibrium Height
is mathematically given as



The answer is letter C. <span>A train travels from the bottom of a hill to the top of a hill, its moves slower by the time it reaches the top is an example of negative acceleration.
In physics, acceleration can be described as an objects change of velocity. When an object gains velocity, it is positive acceleration, and negative acceleration for the opposite.
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