I dont thimk their is a question. Could you be more specific
Answer:
Explanation: Carbon and silicon BOTH come from Group 14 of the Periodic Table , i.e. both formally have the same number of valence electrons, 4 such electrons.........
Answer:
By decreasing the volume, the equilibrium will shift to the side with the smallest amount of particles
Explanation:
Step 1: Data given
The principle of Le Chatelier says:
When the volume is decreased, the equilibrium will shift to the side of the smallest number of particles.
2NOBr(g) ⇌ 2NO(g)+Br2(g)
In the following example, we have 2 moles of NOBr (on the left side) and 3 moles of gas on the right side. This means the left side, the reactant side, has the smallest number of particles.
The equilibrium will here shift to the left side, the side of NOBr.
In the following example
2NO2(g) ⇌ N2O4(g)
We have 2moles of NO2 on the left side and 1 mol of N2O4 on the right side.
By decreasing the volume, the equilibrium will shift to the side of the smallest number of moles. Here this is the right side, the side of N2O4.
Answer: ![[OH^{-}]= 0.01M or 1.0\times 10^{-2}M](https://tex.z-dn.net/?f=%5BOH%5E%7B-%7D%5D%3D%200.01M%20or%201.0%5Ctimes%2010%5E%7B-2%7DM)
![[H^{+}]= 1.0\times 10^{-12}M](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%3D%201.0%5Ctimes%2010%5E%7B-12%7DM)
pH = 12
pOH = 2
Explanation: Calcium hydroxide (
) is a strong base that dissociates completely.
Dissociation equation of Calcium hydroxide is :
1. Concentration of [OH-]
1 mol produces 2 mol OH- ions.
The given solution is 0.005M , then concentration of OH- would be twice the concentration of
![[OH^{-}] = 0.005\times 2](https://tex.z-dn.net/?f=%5BOH%5E%7B-%7D%5D%20%3D%200.005%5Ctimes%202%20)
= 0.01M or 
2.Concentration of [H+]
Concentration of [H+] can be calculated by the formula: ![[H^{+}] = \frac{Kw}{[OH^{-}]}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%20%3D%20%5Cfrac%7BKw%7D%7B%5BOH%5E%7B-%7D%5D%7D)
kw = ionic product of water and its values is 
[OH-] = 0.01 M or
![[H^{+}] = \frac{(1\times 10^{-14})}{[OH^{-}]}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%20%3D%20%5Cfrac%7B%281%5Ctimes%2010%5E%7B-14%7D%29%7D%7B%5BOH%5E%7B-%7D%5D%7D)
![[H^{+}] = \frac{(1\times 10^{-14})}{[0.01]}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%20%3D%20%5Cfrac%7B%281%5Ctimes%2010%5E%7B-14%7D%29%7D%7B%5B0.01%5D%7D)
![[H^{+}] = 1.0\times 10^{-12}M](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%20%3D%201.0%5Ctimes%2010%5E%7B-12%7DM%20)
3. pH value
pH is calculated by the formula : ![pH = -log[H^{+}]](https://tex.z-dn.net/?f=pH%20%3D%20-log%5BH%5E%7B%2B%7D%5D)
![pH = -log[1.0\times 10^{-12}]](https://tex.z-dn.net/?f=pH%20%3D%20-log%5B1.0%5Ctimes%2010%5E%7B-12%7D%5D)
pH = 12
4. pOH value
pOH is calculated by the formula : pOH = 14 - pH
pOH = 14 - 12
pOH = 2
pOH can also be calculated by using a different formula which is :
pOH = 2.
