I know what you are wondering and the answer is simply crystals are more dense than water , so they sink but if you warm it up they can combine with it to become one.
dose this help?
Answer: The time required for the impluse passing through each other is approximately 0.18seconds
Explanation:
Given:
Length,L = 50m
M/L = 0.020kg/m
FA = 5.7×10^2N
FB = 2.5×10^2N
The sum of distance travelled by each pulse must be 50m since each pulse started from opposite ends.
Ca(t) + CB(t) = 50
Where CA and CB are the velocities of the wire A and B
t = 50/ (CA + CB)
But C = Sqrt(FL/M)
Substituting gives:
t = 50/ (Sqrt( FAL/M) + Sqrt(FBL/M))
t = 50/(Sqrt 5.7×10^2/0.02) + (Sqrt(2.5×10^2/0.02))
t = 50 / (168.62 + 111.83)
t = 50/280.15
t = 0.18 seconds
vector A has magnitude 12 m and direction +y
so we can say

vector B has magnitude 33 m and direction - x

Now the resultant of vector A and B is given as

now for direction of the two vectors resultant will be given as


so it is inclined at 160 degree counterclockwise from + x axis
magnitude of A and B will be


so magnitude will be 35.11 m
The data set that is most likely from the car equipped with ABS is :
<u><em>Although the plots related to your question is missing attached below is the missing data. </em></u>
The First plot ( acceleration vs time ) plot is the data that represents the application of brakes in a car fitted with ABS ( antilock braking system ) because of the absence of skidding effect between 6.5 and 9 seconds in the graph.
The skidding effect is present in the second plot around the same time because the car is not fitted with ABS
Hence we can conclude that the graph that shows the car fitted with ABS is the first plot .
Learn more : brainly.com/question/4360615
Answer:
9.4 m/s
Explanation:
The work-energy theorem states that the work done on an object is equal to the change in kinetic energy of the object.
So we can write:

where in this problem:
W = -36.733 J is the work performed on the car (negative because its direction is opposite to the motion of the car)
is the initial kinetic energy of the car
is the final kinetic energy
Solving for Kf,

The kinetic energy of the car can be also written as

where:
m = 661 kg is the mass of the car
v is its final speed
Solving, we find
