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Ierofanga [76]
2 years ago
8

Help help hep help???????????

Physics
1 answer:
Sergeu [11.5K]2 years ago
3 0

Momentum

mava + mbvb = mava '+ mbvb'

(300 x 10)+(150 x 0) = (300 x 4.12)+(150 x vb')

3000=1236+150vb'

1764 = 150vb'

vb'=+11.76 m/s ≈ +11.8 m/s (positive sign, to the right)

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Why does sugar sink to the bottom of the teacup (for science btw)
TEA [102]
I know what you are wondering and the answer is simply crystals are more dense than water , so they sink but if you warm it up they can combine with it to become one.
dose this help?
3 0
2 years ago
Two wires are parallel and one is directly above the other. Each has a length of 50.0 m and a mass per unit length of 0.020 kg/m
ivann1987 [24]

Answer: The time required for the impluse passing through each other is approximately 0.18seconds

Explanation:

Given:

Length,L = 50m

M/L = 0.020kg/m

FA = 5.7×10^2N

FB = 2.5×10^2N

The sum of distance travelled by each pulse must be 50m since each pulse started from opposite ends.

Ca(t) + CB(t) = 50

Where CA and CB are the velocities of the wire A and B

t = 50/ (CA + CB)

But C = Sqrt(FL/M)

Substituting gives:

t = 50/ (Sqrt( FAL/M) + Sqrt(FBL/M))

t = 50/(Sqrt 5.7×10^2/0.02) + (Sqrt(2.5×10^2/0.02))

t = 50 / (168.62 + 111.83)

t = 50/280.15

t = 0.18 seconds

4 0
3 years ago
Read 2 more answers
Vector A⃗ points in the positive y direction and has a magnitude of 12 m. Vector B⃗ has a magnitude of 33 m and points in the ne
gavmur [86]

vector A has magnitude 12 m and direction +y

so we can say

\vec A = 12 \hat j

vector B has magnitude 33 m and direction - x

\vec B = -33 \hat i

Now the resultant of vector A and B is given as

\vec A + \vec B = 12 \hat j - 33 \hat i

now for direction of the two vectors resultant will be given as

\theta = tan^{-1}\frac{12}{-33}

\theta = 160 degree

so it is inclined at 160 degree counterclockwise from + x axis

magnitude of A and B will be

R = \sqrt{A^2 + B^2}

R = \sqrt{12^2 + 33^2} = 35.11 m

so magnitude will be 35.11 m

6 0
3 years ago
The following acceleration vs time plots show
fenix001 [56]

The data set that is most likely from the car equipped with ABS is :

  • The First ( upper ) plot

<u><em>Although the plots related to your question is missing attached below is the missing data.  </em></u>

The First plot ( acceleration vs time ) plot is the data that represents the application of brakes in a car fitted with ABS ( antilock braking system ) because of the absence of skidding effect between 6.5 and 9 seconds in the graph.

The skidding effect is present in the second plot around the same time because the car is not fitted with ABS  

Hence we can conclude that the graph that shows the car fitted with ABS is the first plot .

Learn more : brainly.com/question/4360615

7 0
2 years ago
A car is strapped to a rocket (combined mass = 661 kg), and its kinetic energy is 66,120 J.
Katen [24]

Answer:

9.4 m/s

Explanation:

The work-energy theorem states that the work done on an object is equal to the change in kinetic energy of the object.

So we can write:

W=K_f - K_i

where in this problem:

W = -36.733 J is the work performed on the car (negative because its direction is opposite to the motion of the car)

K_i = 66,120 J is the initial kinetic energy of the car

K_f is the final kinetic energy

Solving for Kf,

K_f = W+K_i = -36,733+66,120=29,387 J

The kinetic energy of the car can be also written as

K_f = \frac{1}{2}mv^2

where:

m = 661 kg is the mass of the car

v is its final speed

Solving, we find

v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(29,387)}{661}}=9.4 m/s

8 0
3 years ago
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