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Alexxx [7]
3 years ago
5

PLSSSSSSS HELP MEHHHHH

Physics
1 answer:
Akimi4 [234]3 years ago
6 0

Answer:

I think no 3rd one is correct

Explanation:

It's my opinion maybe it's wrong

<em>*</em><em>*</em><em>*</em><em>*</em><em>*</em><em>*</em><em>Sorry</em><em> </em><em>if</em><em> </em><em>it</em><em> </em><em>is</em><em> </em><em>wrong</em><em> </em><em>*</em><em>*</em><em>*</em><em>*</em><em>*</em><em>*</em>

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The closest stars are 4 light years away from us. How far away must you be from a 854 kHz radio station with power 50.0 kW for t
Lubov Fominskaja [6]

Answer:

The distance from the radio station is 0.28 light years away.

Solution:

As per the question:

Distance, d = 4 ly

Frequency of the radio station, f = 854 kHz = 854\times 10^{3}\ Hz

Power, P = 50 kW = 50\times 10^{3}\ W

I_{p} = 1\ photon/s/m^{2}

Now,

From the relation:

P = nhf

where

n = no. of photons/second

h = Planck's constant

f = frequency

Now,

n = \frac{P}{hf} = \frac{50\times 10^{3}}{6.626\times 10^{- 34}\times 854\times 10^{3}} = 8.836\times 10^{31}\ photons/s

Area of the sphere, A = 4\pi r^{2}

Now,

Suppose the distance from the radio station be 'r' from where the intensity of the photon is 1\ photon/s/m^{2}

I_{p} = \frac{n}{A} = \frac{n}{4\pi r^{2}}

1 = \frac{8.836\times 10^{31}}{4\pi r^{2}}

r = \sqrt{\frac{8.836\times 10^{31}}{4\pi}} = 2.65\times 10^{15}\ m

Now,

We know that:

1 ly = 9.4607\times 10^{15}\ m

Thus

r = \frac{2.65\times 10^{15}}{9.4607\times 10^{15}} = 0.28\ ly

5 0
3 years ago
The instrument which is commonly used to measure the intensity of radioactivity is called a
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The instrument is a Geiger counter and is used to measure radioactive level around people's bodies.
4 0
3 years ago
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How much work is done to increase the speed of a 1.0 kg toy car by 5.0 m/s?
soldi70 [24.7K]

Answer:

The correct option is (b).

Explanation:

We need to find the work done to increase the speed of a 1 kg toy car by 5 m/s.

We know that, the work done is equal to the kinetic energy of an object i.e.

W=\Delta K\\\\W=\dfrac{1}{2}mv^2\\\\W=\dfrac{1}{2}\times 1\times 5^2\\W=12.5\ J

So, 12.5 J of work is done to increase the speed of a 1.0 kg toy car by 5.0 m/s.

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3 years ago
A vase falls from a windowsill 50.0 m above the sidewalk. How fast is the base moving when it hits the ground?
scZoUnD [109]

Answer:

The answer is A sorry if i'm wrong

Explanation:

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Two postal delivery workers have different routes. They both travel from the post office, to neighborhoods to deliver mail, and
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they travel the same distance

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