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1 year ago

Did you complete today’s physical activity, as outlined in the Fitness Plan?

Physics

1 answer:

Dmitry [639]1 year ago

5 0

Answer:

yes?

Explanation:

I don’t really understand your question

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A cell of e.M.F 1.5v and internal resistance 2.5ohm is connected in series with an ammeter of resistance 0.5ohm. Calculate the c

Tju [1.3M]

Given :

A cell of e.m.f 1.5 V and internal resistance 2.5 ohm is connected in series with an ammeter of resistance 0.5 ohm.

To Find :

The current in the circuit.

Solution :

We know, resistance of the ammeter is in series with the circuit.

So, total resistance is :

R = 2.5 + 0.5 ohm

R = 3 ohm

Also, e.m.f applied is 1.5 V .

Now, by ohm's law :

$I = \dfrac{V}{R}\\\\I = \dfrac{1.5}{3}\\\\I = 0.5 \ A$

Therefore, the current in the circuit is 0.5 A.

8 0

3 years ago

Two spheres A and B of negligible dimensions and masses 1 kg and √3 kg respectively, are supported on the smooth circular surfac

alexdok [17]

Answer:

α = π/3

β = π/6

Explanation:

Use arc length equation to find the sum of the angles.

s = rθ

π/20 m = (0.1 m) (α + β)

π/2 = α + β

Draw a free body diagram for each sphere. Both spheres have three forces acting on them:

Weight force mg pulling down,

Normal force N pushing perpendicular to the surface,

and tension force T pulling tangential to the surface.

Sum of forces on A in the tangential direction:

∑F = ma

T − m₁g sin α = 0

T = m₁g sin α

Sum of forces on B in the tangential direction:

∑F = ma

T − m₂g sin β = 0

T = m₂g sin β

Substituting:

m₁g sin α = m₂g sin β

m₁ sin α = m₂ sin β

(1 kg) sin α = (√3 kg) sin (π/2 − α)

1 sin α = √3 cos α

tan α = √3

α = π/3

β = π/6

4 0

4 years ago

wo skaters collide and embrace in an inelastic collision. Alex's mass is 90 kg and his initial velocity is 1.5 m/s i . Barbara's

Natalija [7]

Answer:

The two skaters will move with a common speed of 1.19 m/s.

Explanation:

Given that,

Mass of Alex, $m_1=90\ kg$

Initial velocity of Alex, $u_1=1.5i\ m/s$

Mass of Barbara, $m_2=57\ kg$

Initial velocity of Barbara, $u_2=2j\ m/s$

After the collision, the two skaters move together at a common velocity. Let V is the common velocity. Using the conservation of momentum as :

$m_1u_1+m_2u_2=(m_1+m_2)V\\\\90\times 1.5i+57\times 2j=(90+57)V\\\\V=\dfrac{135i+114j}{147}\\\\V=\dfrac{135i}{147}+\dfrac{114j}{147}\\\\V=(0.91i+0.77j)\ m/s$

Magnitude of final velocity:

$|V|=\sqrt{0.91^2+0.77^2} \\\\|V|=1.19\ m/s$

So, the two skaters will move with a common speed of 1.19 m/s.

3 0

4 years ago

Read 2 more answers

A motorcyclist drives from a to b with the uniform speed of 30 km/h-1 and returns back with the speed of 20 km/h-1.find the aver

maxonik [38]

30+20 =50
For average 50/2=25

4 0

3 years ago

Read 2 more answers

What are some methods that astronomers use to study interstellar dust?

larisa [96]

Answer:

is to observe through the telescope, study stars inside of the nebula and sometime enhance he pcture to see the real color of the nebula. hopes this helps.

6 0

3 years ago