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1 year ago

Please help! It has to deal with Newton's 3rd law! 30 points! and if right brainliest!

Physics

2 answers:

lorasvet [3.4K]1 year ago

7 0

I think the answer is b :)

Lynna [10]1 year ago

5 0

Answer:

Newton's Third Law

His third law states that for every action (force) in nature there is an equal and opposite reaction

Explanation:

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Where on the Earth would you have to be to see the North Celestial Pole exactly halfway between your horizon and zenith?

mario62 [17]

Answer:

The point straight overhead on the celestial sphere for any observer is called the zenith and is always 90 degrees from the horizon. The arc that goes through the north point on the horizon, zenith, and south point on the horizon is called the meridian.

From any location on Earth you see only half of the celestial sphere, the half above the horizon.

If you stood at the North Pole of Earth, for example, you would see the north celestial pole overhead, at your zenith. The celestial equator, 90° from the celestial poles, would lie along your horizon.

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3 years ago

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Mice21 [21]

Answer:

1.) Radio

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Explanation:

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3 years ago

The Greek root ology means "the study of." The suffix -ist means "one who studies or practices something." Using those definitio

Ann [662]

AnswerA tell me what u got sorry if its worng

Explanation:

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3 years ago

While bats emit a wide variety of sounds, one type emits pulses of sound at a frequency between 39 kHz and 78 kHz. What is the r

sdas [7]

Answer:

The range of wavelengths of the sound is 7692.30 m and 3846.15 m

Explanation:

A bat emits pulses of sound at a frequency between 39 kHz and 78 kHz. It is required to find the range of wavelengths of this sound.

Bat uses ultrasonic waves. It moves with the speed of light.

If f = 39 kHz,

$\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{39\times 10^3}\\\\\lambda=7692.30\ m$

If f = 78 kHz,

$\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{78\times 10^3}\\\\\lambda=3846.15\ m$

So, the range of wavelengths of the sound is 7692.30 m and 3846.15 m.

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3 years ago

Question:<br> the distance of the car can move by velocity 15 m/s for time 5s is :<br> Physics

tangare [24]

Answer:

c) 2.05

Explanation:

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2 years ago