Answer:
the sound intensity at the position of the microphone is 7.4 × 10⁻⁴ W/m²
Explanation:
Given the data in the question;
Sound power P = 26.0 W
Area of microphone A = 1.00 cm²
Radius r = 53.0 m
sound intensity at the position of the microphone = ?
Now, intensity at the position of the microphone can be determined using the following expression;
= P / 4πr²
We substitute
= 26.0 / ( 4 × π × (53.0 )² )
= 26.0 / ( 4 × π × 2809 )
= 26.0 / 35298.935
= 26.0 / ( 4 × π × (53.0 )² )
= 0.000736566
= 7.4 × 10⁻⁴ W/m²
Therefore, the sound intensity at the position of the microphone is 7.4 × 10⁻⁴ W/m²
2.5 percent is fresh and only one present is easy to get.
Keeps everything in balance and keep's the oxygen in place here on earth
Answer:
A shunt is a low-ohm resistor that can be used to measure current. ... The entire current flows through the shunt and generates a voltage drop, which is then is measured. Using Ohm's law and the known resistance, this measurement can then be used to calculate the current (I = V/R).