1st let's calculate the decreasing rate & let V₁ be the initial value & V₂ the final's
we know that V₂=V₁.e^(r,t) where r=rate & t-time (& e=2.718)
After t= 2 years we can write the following formula
2350,000=240,000.e^(2r)==> 235,000/240000 = e^(2r) =>47/48=e^(2r)
ln(47/48)=2rlne==> ln(47/48)=2rlne=2r (since lne =1)
r= ln(47/48)/2==>r=-0.0210534/2 =-0.01052 ==> (r=-0.01052)
1) Determine when the value of the home will be 90% of its original value.
90% of 240000 =216,000
Now let's apply the formula
216,000=240,000,e^(-0.01052t), the unknown is t. Solving it by logarithm it will give t=10 years
1.a) Would the equation be set up like so: V=240e^.09t? NON, in any case if you solve it will find t=1 year
2)Determine the rate at which the value of the home is decreasing one year after : Already calculated above :(r=-0.01052)
3)The relative rate of change : it's r = -0.01052
Let y=x+6 be equation 1...
Replace equation 1 in equation 2
X+6 =-2x-3
X+2x = -3 -6
3x = -9
X = -3
Answer:
see explanation
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h. k) are the coordinates of the vertex and a is a multiplier
here (h, k) = (- 6, - 1), thus
y = a(x + 6)² - 1
To find a substitute one of the roots into the equation
Using (- 3, 0), then
0 = a(- 3 +6)² - 1
0 = 9a - 1 ( add 1 to both sides )
1 = 9a ( divide both sides by 9 )
a =
, thus
y =
(x + 6)² - 1 ← in vertex form
Expand factor and simplify
y =
(x² + 12x + 36) - 1 ← distribute
y =
x² +
x + 4 - 1
=
x² +
x + 3 ← in standard form
Answer:
30b^5 - 20b^3
Step-by-step explanation:
5b^3(6b^2 - 4)
When you multiply numbers with exponents, you add the exponents.
5b^3 * 6b^2 = 30b^5
5b^3 * -4 = -20b^3
30b^5 - 20b^3