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JulijaS [17]
3 years ago
10

Two students created a list of steps for the following construction. Which student has steps in the correct order, and which doe

s not? Explain.
You are given and point C. Construct a line parallel to that passes through point C.


Student A Steps:

Student B Steps:

Draw a line that intersects points B and C.

Draw a line through point C and point G.

Keep the compass at the same width, and place it on point C.

Keeping the compass at the same width, place it on point F.

Mark the intersection of the two arcs as point G.

Open the compass to the width between points D and E.

Place the compass on point B, and swing an arc that crosses line AB and line BC. Label the points D and E.

Swing an arc that crosses line BC, and label the point F.

Swing an arc that intersects the arc created from line BC at point C.

Draw a line that intersects points B and C.

Place the compass on point B, and swing an arc that crosses line AB and line BC. Label the points D and E.

Keep the compass at the same width, and place it on point C.

Swing an arc that crosses line BC, and label the point F.

Open the compass to the width between points D and E.

Keeping the compass at the same width, place it on point F.

Swing an arc that intersects the arc created from line BC at point C.

Mark the intersection of the two arcs as point G.

Draw a line through point C and point G.
Mathematics
1 answer:
irina [24]3 years ago
8 0

Answer:

Step-by-step explanation:

As it is impossible to understand who have done what ,

the correct construction should be :

You are given point A, point B and point C.

Construct a line parallel to that line AB passing through point C.

1) Place the compass on point B, and swing an arc that crosses line AB and line BC.

  Label the points D and E.

2) Keep the compass at the same width, and place it on point C.

3) Swing an arc that crosses line BC, and label the point F outside the segment [BC] .

4) Open the compass to the width between points D and E.

  Keeping the compass at the same width, place it on point F.

5) Swing an arc that intersects the arc created from line BC at point C.

6) Mark the intersection of the two arcs as point G.

7) Draw a line through point C and point G.

<u>You just have to discover who has done that.</u>

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The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly
Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between \\ (\mu - 6\sigma) and \\ (\mu + 6\sigma). It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027

For those with defects <em>operating at a 6 sigma level, </em>the probability is:

\\ 1 - p = 1 - 0.999999998027 = 0.000000001973

Similarly, for finding <em>no defects</em> in a 5 sigma level, we have:

\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697.

The probability of defects is:

\\ 1 - p = 1 - 0.999999426697 = 0.000000573303

Well, the defects present in a six sigma level and a five sigma level are, respectively:

\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}

\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}  

Then, comparing both fractions, we can confirm that a <em>6 sigma level is markedly different when it comes to the number of defects present:</em>

\\ {6\sigma} \approx \frac{2}{10^9} [1]

\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9} [2]

Comparing [1] and [2], a six sigma process has <em>2 defects per billion</em> opportunities, whereas a five sigma process has <em>600 defects per billion</em> opportunities.

8 0
3 years ago
Guys please help me
stich3 [128]

Answer: (x + [-1], y + [1])

Step-by-step explanation:

      <em>See attached. </em>We can draw, or picture it in our heads, what the reflection would look like. Then we can pick one (or multiple to test) points and see the translation.

      We can also test with a set of points. B', (2, 4) becomes G in the transformation. G is at (1, 5)

      (1 - 2, 5 - 4) -> (-1, 1)

8 0
1 year ago
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Len [333]

Answer:

reflection on the y axis

Step-by-step explanation:

it flips from side to side

4 0
3 years ago
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Inessa05 [86]

Answer:

c

Step-by-step explanation:

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6 0
3 years ago
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Find the product using model or drawing
Ganezh [65]

Answer:

1.2/15

2.4/11

3.1/12

4.2/23

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6.51

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8.30

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Step-by-step explanation:

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5 0
3 years ago
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