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garik1379 [7]
2 years ago
10

6+3x=7-x. pls solve and i will mark you brainliest

Mathematics
2 answers:
ycow [4]2 years ago
4 0

⇛6 + 3x = 7 - x

⇛3x + x = 7 - 6

⇛4x = 1

⇛x = 1/4

vampirchik [111]2 years ago
4 0

Answer:

x=0.25 or 1/4

Step-by-step explanation:

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Hendrick wants to enlarge a photo that is 4 inches wide and 6 inches tall. The enlarged photo keeps the same ratio. How y'all is
zhuklara [117]

Answer:

Step-by-step explanation:

Alright, lets get started.

The original photo size is 4 inches wide and 6 inches tall.

So, the ratio of width and height will be = \frac{4}{6}=\frac{2}{3}

The new enlarged photo will be of the same ratio means 2:3

The width of enlarged photo is given as 12 inches.

Suppose new height of enlarged photo is H, so

\frac{12}{H}=\frac{2}{3}

Cross multiplying

2H=36

Dividing 2 in both sides

H=18 inches

So the height of new enlagred photo will be 18 inches.  :   Answer

Hope it will help :)





7 0
3 years ago
Can someone answer this really fast?
Vikki [24]

Answer:

Use your brain

Step-by-step explanation:

Because

6 0
3 years ago
Read 2 more answers
Three students attempt to define what it means for lines lll and mmm to be perpendicular.
Vanyuwa [196]

Please find diagram attached

Answer and explanation:

Perpendicular lines are lines that meet at 90 degrees/ right angle.

The question seems to be incomplete but I will explain what perpendicular lines are in the context of lines lll and mmm, with some assumptions about the lines.

Assume that line III is 30mm long and line mmm is 25mm long, we say that line III is perpendicular to line mmm if line III meets line mmm at 90 degrees as we see in the diagram attached.

7 0
3 years ago
1) Given: circle k(O), ED= diameter ,m∠OEF=32°, m(arc)EF=(2x+10)° Find: x
qaws [65]

1. The major arc ED has measure 180 degrees since ED is a diameter of the circle. The measure of arc EF is (2x+10)^\circ, so the measure of arc DF is

m\widehat{DF}=360^\circ-180^\circ-(2x+10)^\circ=(170-2x)^\circ

The inscribed angle theorem tells us that the central angle subtended by arc DF, \angle DOF, has a measure of twice the measure of the inscribed angle DEF (which is the same angle OEF) so

m\angle DOF=2m\angle OEF=64^\circ

so the measure of arc DF is also 64 degrees. So we have

170-2x=64\implies106=2x\implies\boxed{x=53}

###

2. Arc FE and angle EOF have the same measure, 56 degrees. By the inscribed angle theorem,

m\angle EOF=2m\angle EDF\implies56^\circ=2m\angle EDF\implies m\angle EDF=28^\circ

Triangle DEF is isosceles because FD and ED have the same length, so angles EFD and DEF are congruent. Also, the sum of the interior angles of any triangle is 180 degrees. It follows that

m\angle EFD+m\angle EDF+m\angle DEF=180^\circ\implies\boxed{m\angle EFD=76^\circ}

Triangle OFE is also isosceles, so angles EFO and FEO are congruent. So we have

m\angle EFO+m\angle FEO+m\angle EOF=180^\circ\implies\boxed{m\angle EFO=62^\circ}

7 0
2 years ago
anthony bought an 8 foot board.He cut off 3/4 of the board to build a shelf,and gave 1/3 of the rest to his brother for an art p
e-lub [12.9K]
Convert your feet to inches.
So 8 times by 12 = 96 inches
if you have 3/4 of the board used. 
3/4= .75 
if you were to times 96 by .75 = 72 inches.
So you used 72 inches and you have 24 inches left

now do 1/3= .33
times .33 by 24= 8
8 inches is how long you would give to Anthony's brother.
7 0
3 years ago
Read 2 more answers
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