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3 years ago

True or False

Chemistry

2 answers:

andrey2020 [161]3 years ago

8 0

False. Electromagnetic and Gravitational forces can overcome .

Natali5045456 [20]3 years ago

8 0

Answer:

True

Explanation:

The strong nuclear force is at times more rapidly than the electromagnetic force (EM). In essence, this can be given by the relationship:

$\frac{1}{r^{-7} }$ instead of $\frac{1}{r^{-2} }$

Therefore, the strong proton – proton repulsion between two atoms with smaller radii is able to overcome to overcome non-charge forces, in this case, the gravitational and electromagnetic forces.

Protons and neutron exist of quarks. It requires a strong magnetic force to overcome the strong residual repulsion between two protons.

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What is the composition, in atom percent, of an alloy that contains a) 45.5 lbm of silver, b) 83.7 lbm of gold, and c) 6.3 lbm o

lyudmila [28]

Answer:

$\% atAg=44.6\%\\\% atAu=44.9\%\\\% atCu=10.5\%$

Explanation:

Hello,

In this case, for computing the atom percent, one must obtain the number of atoms of silver, gold and copper as shown below:

$atomsAg=45.5lbm*\frac{453.59g}{1lbm}*\frac{1molAg}{107.87gAg}*\frac{6.022x10^{23}atomsAg}{1molAg}=1.15x10^{26}atomsAg\\atomsAu=83.7lbm*\frac{453.59g}{1lbm}*\frac{1molAu}{196.97gAu}*\frac{6.022x10^{23}atomsAu}{1molAu}=1.16x10^{26}atomsAu\\atomsCu=6.3lbm*\frac{453.59g}{1lbm}*\frac{1molAg}{63.55gCu}*\frac{6.022x10^{23}atomsCu}{1molCu}=2.71x10^{25}atomsCu$

Thus, the atom percent turns out:

$\% atAg=\frac{1.15x10^{26}}{1.15x10^{26}+1.16x10^{26}+2.71x10^{25}}*100\% =44.6\%\\\% atAu=\frac{1.16x10^{26}}{1.15x10^{26}+1.16x10^{26}+2.71x10^{25}}*100\% =44.9\%\\\% atCu=\frac{2.71x10^{25}}{1.15x10^{26}+1.16x10^{26}+2.71x10^{25}}*100\% =10.5\%$

Best regards.

4 0

3 years ago

Will give branliest

fomenos

60 Grams are produced due to the fact that it may not produce more due to the certain capacity that varies on the size of the cube.

5 0

2 years ago

In a high-mass star, hydrogen fusion occurs via the choose one: a. spin-spin interaction. b. proton-proton chain. c. cno cycle.

Lerok [7]

In a high-mass star, hydrogen fusion occurs via the CNO (Carbon-Nitrogen-Oxygen) cycle.

According to the life cycle of a star, there are three main phases in the life of a star: The initial phase (a quick phase), short phase or supergiant phase and death phase or supernova explosion.

the CNO cycle means Carbon-Nitrogen-Oxygen cycle and this process tale place during main sequence phase.

In this phase, hydrogen fuses into helium as a result of six different reaction taking place inside a star.

The first step of the sequence begins when the nucleus of carbon 12 isotope emits gamma rays after capturing a proton and produces nitrogen-13.

This whole cycle is known as stellar nucleosynthesis.

If you need to learn more about Carbon-Nitrogen Cycle click here:

brainly.com/question/13022835

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8 0

2 years ago

What is a joule?

Roman55 [17]

A joule is defined as the amount of energy transferred to an object when a force of one newton acts on the object in the direction of its motion through a distance of one meter (1 newton meter or Nm)

3 0

3 years ago

Read 2 more answers

Convert the following Grams: 0.200 moles of H2S

ANEK [815]

Answer:

6.82 g H₂S

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Atomic Structure

Reading a Periodic Table

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

0.200 mol H₂S

Step 2: Identify Conversions

Molar Mass of H - 1.01 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of H₂S - 2(1.01) + 32.07 = 34.09 g/mol

Step 3: Convert

Set up: $\displaystyle 0.200 \ mol \ H_2S(\frac{34.09 \ g \ H_2S}{1 \ mol \ H_2S})$
Multiply: $\displaystyle 6.818 \ g \ H_2S$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

6.818 g H₂S ≈ 6.82 g H₂S

7 0

3 years ago