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Roman55 [17]
3 years ago
14

True or False

Chemistry
2 answers:
andrey2020 [161]3 years ago
8 0
False. Electromagnetic and Gravitational forces can overcome .
Natali5045456 [20]3 years ago
8 0

Answer:

True

Explanation:

The strong nuclear force is at times more rapidly than the electromagnetic force (EM). In essence, this can be given by the relationship:

\frac{1}{r^{-7} } instead of \frac{1}{r^{-2} }

Therefore, the strong proton – proton repulsion between two atoms with smaller radii is able to overcome to overcome non-charge forces, in this case, the gravitational and electromagnetic forces.

Protons and neutron exist of quarks. It requires a strong magnetic force to overcome the strong residual repulsion between two protons.  

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In a certain chemical process, water reacts with a compound, and the water is converted into another compound during the reactio
gtnhenbr [62]

Answer:

hydration reaction

Explanation:

The type of reaction would be hydration reaction.

<u>Hydration reaction generally involves a chemical reaction of water with another reactant and in which the water ends up being converted to another product entirely. </u>

A good example of hydration reaction is the reaction between alkene and water leading to the production of alcohol.

CH_2=CH_2(g)   +   H_2O(g)  ⇄  CH_3CH_2OH(g)

8 0
3 years ago
Read 2 more answers
How many grams of octane (C8H18) must be burned to produce 300.0g of CO2?
nika2105 [10]

Answer:

m_{C_8H_{18}}=85.67gC_8H_{18}

Explanation:

Hello there!

In this case, according to the given combustion reaction of octane, it is possible for us to perform the stoichiometric method in order to calculate the mass of octane that is required to consume 300.0 g of oxygen by considering the 2:25 mole ratio, and the molar masses of 114.22 g/mol and 32.00 g/mol respectively:

m_{C_8H_{18}}=300.0gO_2*\frac{1molO_2}{32.00gO_2}*\frac{2molC_8H_{18}}{25molO_2}*\frac{114.22gC_8H_{18}}{1molC_8H_{18}}   \\\\m_{C_8H_{18}}=85.67gC_8H_{18}

Regards!

6 0
3 years ago
PLS HELP 6TH GRADE ITS ONE QUESTION ABOUT SCIENCE
julia-pushkina [17]

Answer: The answer is C

Explanation:

5 0
3 years ago
Read 2 more answers
For each molecule, specify the polarity of the bonds and the overall polarity of the molecule.
olasank [31]
Each Be–Cl bond is polar because the two atoms have different electronegativities. The number of outer atoms (2) and lone pairs on the central atom (0) indicate that this molecule has a linear geometry. The bonds in a linear molecule are symmetric, and so their dipoles cancel out.

Each O–H bond is polar because the two atoms have different electronegativities. The number of outer atoms (2) and lone pairs on the central atom (2) indicate that this molecule has a bent geometry. The bonds in a bent molecule are asymmetric, and so their dipoles do not cancel out. In addition, the asymmetric arrangement of the lone pairs on O further contribute to the dipole of this molecule.

An O–O or O=O bond is nonpolar because the two atoms have the same electronegativity. Because there is no overall polarity in O2, the molecule is nonpolar.
5 0
3 years ago
Phosphorus trichloride gas and chlorine gas react to form phosphorus pentachloride gas: PCl3(g)+Cl2(g)⇌PCl5(g). A 7.5-L gas vess
Tpy6a [65]

Answer:

The equilibrium constant in terms of concentration that is, K_c=3.6243\times 10^{3} .

Explanation:

PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

The relation of K_c\& K_p is given by:

K_p=K_c(RT)^{\Delta n_g}

K_p= Equilibrium constant in terms of partial pressure.=98.1

K_c= Equilibrium constant in terms of concentration  =?

T = temperature at which the equilibrium reaction is taking place.

R = universal gas constant

\Delta n_g = Difference between gaseous moles on product side and reactant side=n_{g,p}-n_{g.r}=1-2=-1

98.1=K_c(RT)^{-1}

98.1 =\frac{K_c}{RT}

K_c=98.1\times 0.0821 L atm/mol K\times 450 K=3,624.30=3.6243\times 10^{3}

The equilibrium constant in terms of concentration that is, K_c=3.6243\times 10^{3} .

5 0
3 years ago
Read 2 more answers
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