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avanturin [10]
2 years ago
14

Please help chemistry ASAP Will give brainly

Chemistry
2 answers:
Colt1911 [192]2 years ago
5 0

Answer:

B

Explanation:

Helen [10]2 years ago
3 0
B is the answer

I double checked hope it helps
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Which of the following statements about the kinetic molecular theory are not correct?
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Answer:

The false statement is: (C) The average kinetic energy of the molecules is not related to the absolute temperature

Explanation:

According to the Kinetic Theory of Gases, gases are composed of <u>small fast moving particles that are in constant random motion</u>. These gaseous particles are known as molecules.

It is assumed that the mass of all the gaseous molecules is the same and the <u><em>intermolecular interactions (attractive or repulsive) are negligible</em></u>.

Also, the <em><u>total volume of all the gaseous molecules is considered to be negligible as compared to the volume of the container.</u></em>

According to this theory, <em><u>average kinetic energy (K) of the gaseous particles is directly proportional to the absolute temperature (T) of the gas, </u></em>by the equation:

K = \frac{3}{2}k_{b}T

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<u>Therefore, the false statement about the kinetic molecular theory is (C)</u>

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3 years ago
What are some consequences of using land as a resource
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Urban development has been linked to many environmental problems, including air pollution, water pollution, and loss of wildlife habitat. Urban runoff often contains nutrients, sediment and toxic contaminants, and can cause not only water pollution but also large variation in stream flow and temperatures.

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What is the change in enthalpy associated with the combustion of 530 g of methane (CH4)?Report your answer in scientific notatio
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Answer:

-3.0\times 10^4 kJ is the change in enthalpy associated with the combustion of 530 g of methane.

Explanation:

CH_4+2O_2\rightarrow CO_2+2H_2O,\Delta H_{comb}=-890.8 kJ/mol

Mass of methane burnt = 530 g

Moles of methane burnt = \frac{530 g}{16 g/mol}=33.125 mol

Energy released on combustion of 1 mole of methane = -890.8 kJ/mol

Energy released on combustion of 33.125 moles of methane :

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-2.950775\times 10^4 kJ\approx -3.0\times 10^4 kJ

-3.0\times 10^4 kJ is the change in enthalpy associated with the combustion of 530 g of methane.

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At STP, which sample contains the same number of molecules as 3.0 liters of hydrogen gas?
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