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Neko [114]
3 years ago
12

4) The Maunder Minimum would include which of the following years? A. 1855 - 1900 B. 1910 - 1930 C. 1979 - 1987 D. 1670 - 1700 S

ubmit
Chemistry
1 answer:
ivolga24 [154]3 years ago
4 0
The answer is B 
have a nice day.....

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What is the numbers to the C02
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413.20 ppm

Explanation:

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Which statement best describes the relationship between observations and conclusions? A. Observations are based on Conclusions B
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B. Conclusions are based on observations

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Complete the table to summarize the properties of the different subatomic particles. Type in your answers.
Aloiza [94]

<h2>Complete the table to summarize the properties of the different subatomic particles. </h2>

Explanation:

Atom

It is a smallest particle which cant exist independently.

According To Dalton, atom was indivisible but later on, it was proved that atom can be subdivided into sub atomic particles called electron, proton & neutron.

These subatomic particles have marked properties .

Proton

  • It was discovered by E.Goldstein .
  • It is positively charged particle
  • It is present in nucleus .
  • Its mass is equal to 1.6726219 × 10⁻²⁷ kilograms

Neutron

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  • It is neutral
  • It is present inside the nucleus .
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Electron

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4 0
3 years ago
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He rate constant of a reaction is 4.55 × 10−5 l/mol·s at 195°c and 8.75 × 10−3 l/mol·s at 258°c. what is the activation energy o
Xelga [282]

Answer : The activation energy of the reaction is, 17.285\times 10^4kJ/mole

Solution :  

The relation between the rate constant the activation energy is,  

\log \frac{K_2}{K_1}=\frac{Ea}{2.303\times R}\times [\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = initial rate constant = 4.55\times 10^{-5}L/mole\text{ s}

K_2 = final rate constant = 8.75\times 10^{-3}L/mole\text{ s}

T_1 = initial temperature = 195^oC=273+195=468K

T_2 = final temperature = 258^oC=273+258=531K

R = gas constant = 8.314 kJ/moleK

Ea = activation energy

Now put all the given values in the above formula, we get the activation energy.

\log \frac{8.75\times 10^{-3}L/mole\text{ s}}{4.55\times 10^{-5}L/mole\text{ s}}=\frac{Ea}{2.303\times (8.314kJ/moleK)}\times [\frac{1}{468K}-\frac{1}{531K}]

Ea=17.285\times 10^4kJ/mole

Therefore, the activation energy of the reaction is, 17.285\times 10^4kJ/mole

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3 years ago
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