Answer:
[CH₃COO⁻] [H⁺] pH
0,1 M 0,0025 M 6,30
0,1 M 0,005 M 6,02
0,1 M 0,01 M 5,70
0,1 M 0,05 M 4,74
0,01 M 0,0025 M 5,22
0,01 M 0,005 M 4,75
0,01 M 0,01 M 3,38
0,01 M 0,05 M 1,40
Explanation:
The equilibrium of sodium acetate is:
CH₃COOH ⇄ CH₃COO⁻ + H⁺ Kₐ = 1,8x10⁻⁵
Where [CH₃COO⁻] are 0,1 M and 0,01 M and [H⁺] are 0,0025 M 0,005 M 0,01 M and 0,05 M.
For [CH₃COO⁻]=0,1 M and [H⁺]=0,0025M the concentrations in equilibrium are:
[CH₃COO⁻] = 0,1 M - x
[H⁺] = 0,0025 M - x
[CH₃COOH] = x
The expression for this equilibrium is:
Ka = ![\frac{[CH3COO^-] [H^+] }{[CH3COOH]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BCH3COO%5E-%5D%20%5BH%5E%2B%5D%20%7D%7B%5BCH3COOH%5D%7D)
Replacing:
1,8x10⁻⁵ = ![\frac{[0,1-x] [0,0025-x] }{[x]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B0%2C1-x%5D%20%5B0%2C0025-x%5D%20%7D%7B%5Bx%5D%7D)
Thus:
0 = x²-0,102518x +2,5x10⁻⁴
Solving:
x = 0,100 ⇒ No physical sense
x = 0,0024995
Thus, [H⁺] = 0,0025-0,0024995 = 5x10⁻⁷
pH = - log [H⁺] = 6,30
Following the same procedure changing both [CH₃COO⁻] and [H⁺] initial concentrations the obtained pH's are:
[CH₃COO⁻] [H⁺] pH
0,1 M 0,0025 M 6,30
0,1 M 0,005 M 6,02
0,1 M 0,01 M 5,70
0,1 M 0,05 M 4,74
0,01 M 0,0025 M 5,22
0,01 M 0,005 M 4,75
0,01 M 0,01 M 3,38
0,01 M 0,05 M 1,40
I hope it helps!
<span>C</span>⁰<span> H</span>₃⁺¹<span> C</span>⁰<span> O</span>⁻²<span> O</span>⁻²<span> H</span>⁺¹
C is 0
H = + 1
O = - 2
A. Shaman
Shaman were revered as people with the ability to communicate with good and evil spirits and heal ailments.
use the periodic table to identify an element is by looking for the element's name or elemental symbol.
1. I think it is true?
2. Low melting points
3. True
4. Atomic number, I think it’s periods?
5. Groups?
Sorry, I might not get all of them right :(
Hope this helps you in any way!!