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ivann1987 [24]
2 years ago
7

2 Upper P Upper O Upper C l Subscript 3 Baseline (g) + heat double-headed arrow 2 Upper P Upper C l Subscript 3 Baseline (g) + U

pper O Subscript 2 Baseline (g) For the equilibrium system described by this equation, what happens if the temperature is decreased?
Chemistry
1 answer:
gregori [183]2 years ago
6 0

Answer:

The equilibrium will shift left.

Explanation:

Hope this helps <3

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Determine the mass percent composition of a solution made by dissolving 40.1g of LiOH in 681g of H2O
Lapatulllka [165]
<h3>Answer:</h3>

5.89%

<h3>Explanation:</h3>

We are given;

  • Mass of the solute, LiOH as 40.1 g
  • Mass of the solvent, H₂O as 681 g

We are required to calculate the mass percent composition of solution;

  • But; How do we calculate the mass percent composition of a solution?
  • We use the formula;
  • Mass composition of a solution = (Mass of solute/mass of solution) 100%
  • Therefore;

Mass Percent = (40.1 g/681 g)× 100%

                       = 5.888 %

                       = 5.89%

Therefore, the mass percent composition of the solution is 5.89%

7 0
3 years ago
What is bias in an experiment?
baherus [9]

Answer:

D.

Explanation:

It pushes the experimental results one way or another.  Less reliable.

5 0
4 years ago
What is the purpose of a catalyst in the production of hydrogen?
lilavasa [31]

Answer:To speed up the rate of hydrogen production

Explanation:

In the preparation of Hydrogen from the action of dilute acid on zinc metal, few drops of Copper(II)tetraoxosulphate(VI) solution is added to speed up the rate of production.

The hydrogen produced is shown in the equation below

Zn(s) + 2HCl(aq) --> ZnCl2(aq) + H2(g)

Thus, Copper(II)tetraoxosulphate(VI) solution, a catalyst is used to speed up hydrogen production.

8 0
3 years ago
A solution was prepared by dissolving 5.76 g of KCl •MgCl2
tankabanditka [31]

a) (10.12 g salt) x [(1 mole salt)/(277.85 g salt)] x [(1)/(2.000 L soln)] = 0.0182 M  

b) (0.0182 M) x [(1 mole Mg2+)/(1 mole salt)] = 0.0182 M  

c) (0.0182 M) x [(3 moles Cl-)/(1 mole salt)] = 0.0546 M  

d) [(10.12 g salt)/(2000 mL)] x 100% = 0.506% (w/v)  

e) (0.0546 M Cl-)(25.0 mL soln) = 1.36 mmoles Cl-  

f) [(0.0182 moles K+) / (1.000 L)] x [(39.10 g K+)/(1 mole K+)] x [(1 L soln)/(1000 g soln)] x (1x10^6) = 712 ppm

3 0
4 years ago
What type of chemical reaction does this equation represent?
NikAS [45]

Answer:

Single Replacement

Explanation:

The oxygen switches from a bond with iron to a bond with carbon.

3 0
3 years ago
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