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Ann [662]
3 years ago
11

A room is 32 feet across. How wide is the room in cm?

Chemistry
1 answer:
Effectus [21]3 years ago
6 0

Answer:

g

Explanation:

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How could you ensure that all the spectroscopes used the same calibration line and equation? What would you need to be sure was
NISA [10]
People had asked this many times and that is why they came up with methods and standards that will answer these type of questions. You can look it up in the NIST or the  National Institute for Standards and Technology.
8 0
3 years ago
A 24.00 mL sample of a solution of Pb(ClO3)2 was diluted with water to 52.00 mL. A 17.00 mL sample of the dilute solution was fo
lara [203]

Answer:

0.238 M

Explanation:

A 17.00 mL sample of the dilute solution was found to contain 0.220 M ClO₃⁻(aq). The concentration is an intensive property, so the concentration in the 52.00 mL is also 0.220 M ClO₃⁻(aq). We can find the initial concentration of ClO₃⁻ using the dilution rule.

C₁.V₁ = C₂.V₂

C₁ × 24.00 mL = 0.220 M × 52.00 mL

C₁ = 0.477 M

The concentration of Pb(ClO₃)₂ is:

\frac{0.477molClO_{3}^{-} }{L} \times \frac{1molPb(ClO_{3})_{2}}{2molClO_{3}^{-}} =0.238M

6 0
3 years ago
For the reaction CO2(g) + H2(g)CO(g) + H20(g)
Studentka2010 [4]

Answer:

The ΔG° is 29 kJ and the reaction is favored towards reactant.

Explanation:

Based on the given information, the ΔH°rxn or enthalpy change is 41.2 kJ, the ΔS°rxn or change in entropy is 42.1 J/K or 42.1 * 10⁻³ kJ/K. The temperature given is 289 K. Now the Gibbs Free energy change can be calculated by using the formula,  

ΔG° = ΔH°rxn - TΔS°rxn

= 41.2 kJ - 289 K × 42.1 × 10⁻³ kJ/K

= 41.2 kJ - 12.2 kJ

= 29 kJ

As ΔG° of the reaction is positive, therefore, the reaction is favored towards reactant.  

5 0
3 years ago
This is for chemistry:/
Andreyy89

Answer:

Its the bottom one :) ......

5 0
3 years ago
What is the answer to the net ionic equation FeO(s)+2HClO4(aq)--> Fe(ClO4)2 (aq)+ H2O(l)
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Feo + 2H = H2O + Fe + 2 + CIO4-
this is ur answer. .
mrk me as brainlist
8 0
3 years ago
Read 2 more answers
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