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Ann [662]
3 years ago
11

A room is 32 feet across. How wide is the room in cm?

Chemistry
1 answer:
Effectus [21]3 years ago
6 0

Answer:

g

Explanation:

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Covert from cm to m plz and thank u:);)
MArishka [77]

Your Answer would be 1.74

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A bottle of sulfuric acid has a mass of 18.45 g and a density of 4.37 g/mL. What is the volume?
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Which of the following solutions would have the lowest freezing point? 1.0 nacl 3.0 nacl 2.0 nacl or 5.0 nacl
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The solution that will have the lowest freezing point is 5.0 SODIUM CHLORIDE. 
Adding solute to solvents usually result in the depression of the freezing point. The higher the quantity of the solute that is added, the lower the freezing point of the solution.
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3 years ago
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Carbon tetrachloride reacts at high temperatures with oxygen to produce two toxic gases, phosgene and chlorine. CCl4(g) + (1/2)O
madam [21]

The question is incomplete, here is the complete question:

Carbon tetrachloride reacts at high temperatures with oxygen to produce two toxic gases, phosgene and chlorine.

CCl_4(g)+\frac{1}{2}O_2(g)\rightleftharpoons COCl_2(g)+Cl_2(g);K_c=4.4\times 10^9 at 1,000 K

Calculate Kc for the reaction 2CCl_4(g)+O_2(g)\rightleftharpoons 2COCl_2(g)+2Cl_2(g)

<u>Answer:</u> The value of K_c' for the final reaction is 1.936\times 10^{19}

<u>Explanation:</u>

The given chemical equations follows:

CCl_4(g)+\frac{1}{2}O_2(g)\rightleftharpoons COCl_2(g)+Cl_2(g);K_c

We need to calculate the equilibrium constant for the equation, which is:

2CCl_4(g)+O_2(g)\rightleftharpoons 2COCl_2(g)+2Cl_2(g)

As, the final reaction is the twice of the initial equation. So, the equilibrium constant for the final reaction will be the square of the initial equilibrium constant.

The value of equilibrium constant for net reaction is:

K_c'=(K_c)^2

We are given:

K_c=4.4\times 10^9

Putting values in above equation, we get:

K_c'=(4.4\times 10^9)^2=1.936\times 10^{19}

Hence, the value of K_c' for the final reaction is 1.936\times 10^{19}

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3 years ago
Can you balance 12 blocks on the 3x2 platform
Jobisdone [24]
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