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larisa [96]
2 years ago
14

What was the control group for this experiment?

Chemistry
1 answer:
vladimir1956 [14]2 years ago
8 0

Answer:

a

Explanation:

the rat felt the normal diet with vitamin are gain weight than the rat felt with diet

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Can Individual atoms be moved and rearranged ?
andriy [413]

Answer:

Yes

Explanation:

Scientists using the latest microscopic technology have found they can move individual atoms around a surface at will, a breakthrough that could have profound implications in the ultra-small world of electronics and even in industry

6 0
3 years ago
My teacher gave this assignment for homework, and I don’t get it. A little help please?
SSSSS [86.1K]

County: cell

State: Tissue

Country: Organ

Continent: Organ system

World: organism

(smallest to largest)

3 0
3 years ago
Matter is made up of small
Lena [83]

Answer:

atoms and molecules

Explanation:

matter is made up of particles called atoms and molecules

4 0
3 years ago
Read 2 more answers
A slice of Swiss cheese contains 47 mg of sodium. (a) What is this mass in grams? .047 (b) What is this mass in ounces? (16 oz =
MAVERICK [17]

Answer:

(a) 0.047 g (b) 0.0016 oz (c) 0.0001 lb

Explanation:

The given mass of the sodium in the slice = 47 mg

(a) Mass has to be calculated in grams

The conversion of mg to g is shown below as:

1 mg = 10⁻³ g

So,

<u>Mass of sodium = 47 × 10⁻³ g = 0.047 g</u>

(b) Mass has to be calculated in ounces

The conversion of ounces to g is shown below as:

453.6 g = 16 oz

Or,

1 g = 16 / 453.6 oz

So,

<u>Mass of sodium = (0.047 × 16) / 453.6 oz = 0.0016 oz</u>

(c) Mass has to be calculated in pounds

The conversion of pounds to g is shown below as:

1 lb = 453.6 g

Or,

1 g = 1/ 453.6 lb

So,

<u>Mass of sodium = (0.047 × 1) / 453.6 oz = 0.0001 lb</u>

5 0
2 years ago
Consider a voltaic cell where the anode half-reaction is Zn(s) → Zn2+(aq) + 2 e− and the cathode half-reaction is Sn2+(aq) + 2 e
notsponge [240]

<u>Answer:</u> The concentration of Sn^{2+} in the cell is 9.0\times 10^{-3}M

<u>Explanation:</u>

We are given:

<u>Oxidation half reaction:</u>  Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-   E^o_{Zn^{2+}/Zn}=-0.76V

<u>Reduction half reaction:</u>  Sn^{2+}(aq.)+2e^-\rightarrow Sn(s)   E^o_{Sn^{2+}/Sn}=-0.136V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Here, tin will undergo reduction reaction and will get reduced.

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=-0.136-(-0.76)=0.624V

To calculate the EMF of the cell, we use the Nernst equation, which is:

E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Mn^{2+}]}{[Cu^{2+}]}

where,

E_{cell} = electrode potential of the cell = 0.660 V

E^o_{cell} = standard electrode potential of the cell = +0.624 V

n = number of electrons exchanged = 2

[Zn^{2+}]=2.5\times 10^{-3}M

[Sn^{2+}] = ?

Putting values in above equation, we get:

0.660=0.624-\frac{0.059}{2}\times \log(\frac{2.5\times 10^{-3}}{[Sn^{2+}})

[Sn^{2+}]=9.0\times 10^{-3}M

Hence, the concentration of Sn^{2+} ions is 9.0\times 10^{-3}M

3 0
3 years ago
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