Answer:
1
Explanation:
Consider the following reaction:
Phosphorus burn in the presence of air and produced diphosphorus pentoxide.
Chemical equation:
P₄ + O₂ → P₂O₅
Balanced chemical equation:
P₄ + 5O₂ → 2P₂O₅
Equation is balanced because there are four phosphorus atoms ans ten oxygen atoms in both side of equation.
Coefficient with reactant and product:
P₄ 1
O₂ 5
P₂O₅ 2
There is no coefficient written before P₄ it means only one P₄ is present.
Answer:
Mass of Na₂CrO₄ = 5.75 g
Explanation:
First of all we will write the balance chemical equation.
2AgNO₃ + Na₂CrO₄ → Ag₂CrO₄ + 2NaNO₃
Now we will calculate the moles of AgNO₃.
Number of moles = mass / molar mass
Molar mass of AgNO₃ = 107.87 + 14 + 3× 16 = 169.87 g/mol
Number of moles = mass / molar mass
Number of moles = 12.1 g / 169.87 g/mol = 0.071 mol
Now we will compare the moles of AgNO₃ and Na₂CrO₄ from balance chemical equation.
AgNO₃ : Na₂CrO₄
2 : 1
0.071 : 1/2× 0.071 = 0.0355
Now we will calculate the mass of Na₂CrO₄.
Molar mass of Na₂CrO₄ = 23×2 + 52 + 16×4 = 162 g/mol
Mass of Na₂CrO₄ = number of moles × molar mass
Mass of Na₂CrO₄ = 0.0355 mol × 162 g/mol
Mass of Na₂CrO₄ = 5.75 g
Answer: 2 PCl3 + 2 Cl2 > 2 PCl5
Explanation: The factors will be 2 moles of PCl3 reacted to 2 moles of chlorine gas Cl2 and the reaction will produce 2 moles of Phosphorous pentachloride PCl5.
For the reactants 2PCl3 +2 Cl2 there will be 2P, Cl (2x3) +
(2x2) so chlorine will have 10. In the product side 2PCl5. 2 P and Cl will have (5x2)=10.
The chemical reaction will have a balance chemical equation.
Answer:
Here's how I would do it.
Explanation:
A Lewis structure shows the valence electrons surrounding the atoms.
1. Identify the central atoms
The central atoms are the least electronegative atoms (C).
I chose as my central atoms a chain of four C atoms: C-C-C-C
I stuck the most electronegative atom (O) at the end of the chain:
C-C-C-C-O
2. Complete the structure
The hydrogen atoms must be terminal. Add enough to give every atom an octet.
You should get a structure like the one below