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trapecia [35]
3 years ago
13

The table below shows two types of electromagnetic waves and three random applications of electromagnetic waves.

Chemistry
2 answers:
Ilia_Sergeevich [38]3 years ago
6 0

CORRECT ANSWER: GAMMA RAYS-1  AND RADIO WAVES-2

<h2>TOOK THE TEST!</h2>
Reptile [31]3 years ago
4 0
Correct Answer is 1 i.e. Gamma rays—2 and radio waves—3

Reason: 
1) In a hypernova, star<span> as similar to </span>nuclear fusion<span> converts lighter elements into heavy elements. If fusion is not capable of generating enough pressure to counteract gravity, star immediately collapses to form a </span>black hole<span>. During this process, energy will be released, along the axis of rotation to form </span>gamma-ray burst. Such gamma-ray burst was first detected using <span>Fermi Gamma-ray Space Telescope. Thus, gamma-ray is capable of providing information of gravity fields.

2) Radiowaves are capable of inducing transitions that requires less energies. These transition includes nuclear excitation and electron excitation (in rotational energy level). Depending upon the value to Jmax, it is possible to determine the temperature and </span><span>heat released by astronomical objects</span><span>
</span>
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The electron configuration for Oxygen : [He] 2s²2p⁴

<h3>Further explanation</h3>

Writing electron configurations starts from the lowest to the highest sub-shell energy level. There are 4 sub-shells in the shell of an atom, namely s, p, d, and f. The maximum number of electrons for each sub-shell is  

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• d: 10 electrons and  

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Charging electrons in the sub-shell uses the following sequence:  

<em>1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², etc.  </em>

The element is Oxgen, with symbol O, and :

the atomic number=8=number of electron

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The electron configuration based on the number of electrons(for Oxygen=8), so the configuration :

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Rb look closely

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