2 years ago

A triangle can have at most___ right angle О 2 4 1

Mathematics

1 answer:

ICE Princess25 [194]2 years ago

6 0

a right angle can have at least 2

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Let f(x)=x+a/x+b such that f(f(1)=0 & f(2)=-3 then a&b resctivily are.

Yuliya22 [10]

Answer:

The value of a = - 1 , And b = $\frac{ - 7 }{3}$

Step-by-step explanation:

Given as :

Function f(x) = $\frac{(x + a)}{(x + b)}$

And f(f(1)) = 0 And f(2) = - 3

Now For , x = 2 , y = - 3

I.e f(2) = $\frac{(2 + a)}{(2 + b)}$

or, - 3 = $\frac{(2 + a)}{(2 + b)}$

I.e 2 + a = - 6 - 3b

Or, a + 3b = - 8 ....... 1

Again f(f(1)) = 0

So, $\frac{(1 + a)}{(1 + b)}$ = 0

Or, 1 + a = 0

∴ a = - 1

So , put htis value of a i n eq 1 , we get value of b

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Or, 3b = - 7

∴ b = $\frac{ - 7 }{3}$

Hence The value of a = - 1 , And b = $\frac{ - 7 }{3}$ Answer

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