Answer:
Alice is correct.
The loop are dependent.
Explanation:
for(i = 1; i <= N; i = (i*2)+17 )
for(k = i+1; k <= i+N; k = k+1) // notice i in i+1 and i+N
printf("B")
This is a nested for-loop.
After the first for-loop opening, there is no block of statement to be executed rather a for-loop is called again. And the second for-loop uses the value of i from the first for-loop. The value of N is both called from outside the loop.
So, the second for-loop depend on the first for loop to get the value of i. For clarity purpose, code indentation or use of curly brace is advised.
Algorithm of the Nios II assembly program.
- Attain data for simulation from the SW11-0, on the DE2-115 Simulator
- The data will be read from the switches in loop.
- The decimal output is displayed using the seven-segment displays and done using the loop.
- The program is ended by the user operating the SW1 switch
and
The decimal equivalent on the seven-segment displays HEX3-0 is
- DE2-115
- DE2-115_SW11
- DE2-115_HEX3
- DE2-115_HEX4
- DE2-115_HEX5
- DE2-115_HEX6
- DE2-115_HEX7
<h3>The Algorithm and
decimal equivalent on the
seven-segment displays HEX3-0</h3>
Generally, the program will be written using a cpulator simulator in order to attain best result.
We are to
- Attain data for simulation from the SW11-0, on the DE2-115 Simulator
- The data will be read from the switches in loop.
- The decimal output is displayed using the seven-segment displays and done using the loop.
- The program is ended by the user operating the SW1 switch
This will be the Algorithm of the Nios II assembly program .
Hence, the decimal equivalent on the seven-segment displays HEX3-0 is
- DE2-115
- DE2-115_SW11
- DE2-115_HEX3
- DE2-115_HEX4
- DE2-115_HEX5
- DE2-115_HEX6
- DE2-115_HEX7
For more information on Algorithm
brainly.com/question/11623795
If your accelerator gets stuck down, do the following: Shift to neutral. Apply the brakes. Keep your eyes on the road and look for a way out.If your accelerator gets stuck down, do the following:
Shift to neutral.
Apply the brakes.
Keep your eyes on the road and look for a way out.
Warn other drivers by blinking and flashing your hazard lights.
Try to drive the car safely off the road.
Turn off the ignition when you no longer need to change direction.
Answer:
Explanation:
a) On the verge of tipping over, reaction acts at the corner A
When slippage occurs,
Block moves w/ const. velocity equilibrium
Three-force member: reaction at A must pass through B
tan b/2h, h b/ 2 θ µ = = ∴= k k ( µ )
b) When slippage occurs,
Block moves w/ const. velocity equilibrium
Three-force member: reaction at C must pass through G
k tanθ µ =
tan x/ H/2 , x H/2
Answer:
import java.util.*;
public class Main {
public static void main(String[] args) {
double milesPerGallon = 0;
int totalMiles = 0;
int totalGallons = 0;
double totalMPG = 0;
Scanner input = new Scanner(System.in);
while(true){
System.out.print("Enter the miles driven: ");
int miles = input.nextInt();
if(miles <= 0)
break;
else{
System.out.print("Enter the gallons used: ");
int gallons = input.nextInt();
totalMiles += miles;
totalGallons += gallons;
milesPerGallon = (double) miles/gallons;
totalMPG = (double) totalMiles / totalGallons;
System.out.printf("Miles per gallon for this trip is: %.1f\n", milesPerGallon);
System.out.printf("Total miles per gallon is: %.1f\n", totalMPG);
}
}
}
}
Explanation:
Initialize the variables
Create a while loop that iterates until the specified condition is met inside the loop
Inside the loop, ask the user to enter the miles. If the miles is less than or equal to 0, stop the loop. Otherwise, for each trip do the following: Ask the user to enter the gallons. Add the miles and gallons to totalMiles and totalGallons respectively. Calculate the milesPerGallon (divide miles by gallons). Calculate the totalMPG (divide totalMiles by totalGallons). Print the miles per gallon and total miles per gallon.
