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Paladinen [302]
3 years ago
7

Water is stored in a tank which has vent open to the atmosphere. The water level is 1.0 m below the top the tank and the water i

s 4 m deep. A siphon with .03 m ID is used to remove water from the tank. The siphon discharge is 6.0 m below the top of the tank. Neglect the friction loss of water through the siphon. Determine the flow rate of water in unit of m^3/s.
Engineering
1 answer:
sp2606 [1]3 years ago
7 0

Answer:

6.99 x 10⁻³ m³ / s

Explanation:

Th e pressure difference at the two ends of the delivery pipe due to atmospheric pressure and water column will cause flow of water.

h = difference in the height of water column at two ends of delivery pipe

6 - 1 =  5 m

Velocity of flow of water

v = √2gh

= √ (2 x 9.8 x 5)

=  9.9 m /s

Volume of water flowing per unit time

velocity x cross sectional area

= 9.9 x 3.14 x .015²

= 6.99 x 10⁻³ m³ / s

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Read 2 more answers
A 4-stroke Diesel engine with a displacement of Vd = 2.5x10^-3m^3 produces a mean effective pressure of 6.4 bar at the speed of
yKpoI14uk [10]

Answer:

The power developed by engine is 167.55 KW

Explanation:

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V_d=2.5\times 10^{-3} m^3

Mean effective pressure = 6.4 bar

Speed = 2000 rpm

We know that power is the work done per second.

So

P=6.4\times 100\times 2.5\times 10^{-3}\times \dfrac{2\pi \times2000}{120}

We have to notice one point that we divide by 120 instead of 60, because it is a 4 cylinder engine.

P=167.55 KW

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4 0
3 years ago
A flat plate 1.5 m long and 1.0 m wide is towed in water at 20 o C in the direction of its length at a speed of 15 cm/s. Determi
beks73 [17]

Answer:

15.8

0.0944

Explanation:

L = 1.5

B = 1.0

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Specific weight = 9790

Kinematic viscosity v = 1.00x10^-4m²/s

Dynamic viscosity u = 1.00x10^-3

Density p = 998kg/m²

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5x1.5/225000^1/2

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= 2N

= 2x0.04724

= 0.0944N

3 0
3 years ago
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