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Vinvika [58]
3 years ago
11

Cup-sveg-aphI m finding gfif anyone interested pls come​

Engineering
2 answers:
cluponka [151]3 years ago
6 0
Go on a dating app and you'll find one
enot [183]3 years ago
3 0

Answer:Chi-raq

Explanation:Nicki Minaj

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A manager who focuses on the employees who enable a company to do business is human resource management. True True False False
nydimaria [60]

Answer:

False.

Explanation:

6 0
3 years ago
The internal loadings at a critical section along the steel drive shaft of a ship are calculated to be a torque of 2300 lb⋅ft, a
Arturiano [62]

Answer:

Explanation:

Given that:

Torque T = 2300 lb - ft

Bending moment M = 1500 lb - ft

axial thrust P = 2500 lb

yield points for tension  σY= 100 ksi

yield points for shear   τY = 50 ksi

Using maximum-shear-stress theory

\sigma_A = \dfrac{P}{A}+\dfrac{Mc}{I}

where;

A = \pi c^2

I = \dfrac{\pi}{4}c^4

\sigma_A = \dfrac{P}{\pi c^2}+\dfrac{Mc}{ \dfrac{\pi}{4}c^4}

\sigma_A = \dfrac{2500}{\pi c^2}+\dfrac{1500*12c}{ \dfrac{\pi}{4}c^4}

\sigma_A = \dfrac{2500}{\pi c^2}+\dfrac{72000c}{\pi c^3}}

\tau_A = \dfrac{T_c}{\tau}

where;

\tau = \dfrac{\pi c^4}{2}

\tau_A = \dfrac{T_c}{\dfrac{\pi c^4}{2}}

\tau_A = \dfrac{2300*12 c}{\dfrac{\pi c^4}{2}}

\tau_A = \dfrac{55200 }{\pi c^3}}

\sigma_{1,2} = \dfrac{\sigma_x+\sigma_y}{2} \pm \sqrt{\dfrac{(\sigma_x - \sigma_y)^2}{2}+ \tau_y^2}

\sigma_{1,2} = \dfrac{2500+72000}{2 \pi c ^3} \pm \sqrt{\dfrac{(2500 +72000)^2}{2 \pi c^3}+ \dfrac{55200}{\pi c^3}} \ \ \ \ \ ------(1)

Let say :

|\sigma_1 - \sigma_2|  = \sigma_y

Then :

2\sqrt{(   \dfrac{2500c + 72000}{2 \pi c^3})^2+ ( \dfrac{55200}{\pi c^3})^2 } = 100(10^3)

(2500 c + 72000)^2 +(110400)^2 = 10000*10^6 \pi^2 c^6

6.25c^2 + 360c+ 17372.16-10,000\ \pi^2 c^6 =0

According to trial and error;

c = 0.75057 in

Replacing  c into equation (1)

\sigma_{1,2} = \dfrac{2500+72000}{2 \pi (0.75057) ^3} \pm \sqrt{\dfrac{(2500 +72000)^2}{2 \pi (0.75057)^3}+ \dfrac{55200}{\pi (0.75057)^3}}

\sigma_{1,2} = \dfrac{2500+72000}{2 \pi (0.75057) ^3} +  \sqrt{\dfrac{(2500 +72000)^2}{2 \pi (0.75057)^3}+ \dfrac{55200}{\pi (0.75057)^3}}  \ \ \  OR \\ \\ \\   \sigma_{1,2} = \dfrac{2500+72000}{2 \pi (0.75057) ^3} -  \sqrt{\dfrac{(2500 +72000)^2}{2 \pi (0.75057)^3}+ \dfrac{55200}{\pi (0.75057)^3}}

\sigma _1 = 22193 \ Psi

\sigma_2 = -77807 \ Psi

The required diameter d  = 2c

d = 1.50 in   or   0.125 ft

6 0
3 years ago
Give me uses of a grinding machine in agriculture.
Tju [1.3M]

Answer:

The grinding machine is used for roughing and finishing flat, cylindrical, and conical surfaces; finishing internal cylinders or bores; forming and sharpening cutting tools; snagging or removing rough projections from castings and stampings; and cleaning, polishing, and buffing surfaces.

4 0
2 years ago
A teacher tells her​ students, "When you do your math homework​ assignments, you must use white lined paper.​ Please, no​ tear-o
Sindrei [870]

Answer:

The white lined paper

Explanation:

The teacher is most likely putting the while line paper in jeopardy because of the detail process involved in taking care of the paper prior to the submission of the home work.

The fact that a mistake must not be visible due to the instruction of every erasures being thorough and clean.  this can cause jeopardy to the paper.

8 0
2 years ago
A discrete MOSFET common-source amplifier has RG = 2 MΩ, gm = 5 mA/V, ro = 100 kΩ, RD = 20kΩ, Cgs = 3pF, and Cgd = 0.5pF. The am
Papessa [141]

Answer:

a) -36.36 V/V

b) 15.17 kHz

c) 1.6 GHz

Explanation:

See attached picture.

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