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Vinvika [58]
3 years ago
11

Cup-sveg-aphI m finding gfif anyone interested pls come​

Engineering
2 answers:
cluponka [151]3 years ago
6 0
Go on a dating app and you'll find one
enot [183]3 years ago
3 0

Answer:Chi-raq

Explanation:Nicki Minaj

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9. How is the Air Delivery temperature controlled during A/C operation?
Rzqust [24]

Answer:

i believe the answer is a but i could be wrong

Explanation:

i hope it helps

6 0
3 years ago
¿Cuándo se formarán cristales en una mezcla que se está evaporando?
Georgia [21]
Answer - La cristalización ye un procesu químicu pol cual a partir d'un gas, un líquidu o una disolución, los iones, átomos o molécules establecen enllaces hasta formar una rede cristalina, la unidá básica d'un cristal. La cristalización emplegar con bastante frecuencia en química para purificar una sustancia sólida.
5 0
3 years ago
It is appropriate to use the following yield or failure criterion for ductile materials (a) Maximum shear stress or Tresca crite
Nataly [62]

Answer:

(b)Distortion energy theory.

Explanation:

The best suitable theory for ductile material:

       (1)Maximum shear stress theory (Guest and Tresca theory)

It theory state that applied maximum shear stress should be less or equal to its maximum shear strength.

      (2)Maximum distortion energy theory(Von Mises henkey's        theory)

It states that maximum shear train energy per unit volume at any point  is equal to strain energy per unit volume under the state of uni axial stress condition.

But from these two Best theories ,suitable theory is distortion energy theory ,because it gives best suitable result for ductile material.

6 0
3 years ago
A right triangle has a base of 12 inches and a height of 30 inches, what is the centroid of the triangle?​
aliina [53]

Answer:

the correct answer is 42

4 0
3 years ago
An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 130 lb and
k0ka [10]

Answer:

A.) 0.3088

B.) 0.0017

C.) part A

Explanation:

A.)

z1= \frac{\left(150-137\right)}{27.7}=0.4693

z2=\frac{\left(201-137\right)}{27.7}=2.3105

P(0.4693

B.)

z1=\frac{150-137}{27.7/ \sqrt{39}} =2.9309\\z2=\frac{201-137}{27.7/ \sqrt{39}}=14.4289

\\P(2.9309

C.) Since the seat performance for an individual pilot is more important than 39 different pilots.

3 0
3 years ago
Read 2 more answers
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