Calculate the rate of loss of heat through a glass window of area 200 CM square and thickness 0.5 CM where temperature inside is
1 answer:
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Answer:
Acceleration,
Explanation:
Given that,
The plane is at rest initially, u = 0
Final speed of the plane, v = 72.2 m/s
Time, t = 29 s
We need to find the average acceleration for the plane. It can be calculated as :
So, the average acceleration for the plane is . Hence, this is the required solution.
The force of frictions is opposed to relative motion.
The acceleration of the crate is approximately <u>2.937 m/s²</u>.
Reason:
The given parameters are;
The mass of the wood, m = 100 kg
The force which can move the wood, F = 588 N
Wood on wood static friction, = 0.5
Wood on wood kinetic friction, = 0.3
Solution;
The force of friction, , acting when the crate is moving is given as
follows;
= m × g ×
Where;
g = The acceleration due to gravity ≈ 9.81 m/s²
Therefore, we have;
= 100 × 9.81 × 0.3 = 294.3
The force of friction, = 294.3 N
The force with which the crate moves, F = 588 - 294.3 = 293.7
The force with which the crate moves, F = 293.7 N
Force = Mass, m × Acceleration, a
Therefore;
The acceleration of the crate, a ≈ <u>2.937 m/s²</u>.
Learn more about friction here:
Answer:
577g
Explanation:
Given parameters:
Temperature change = 5.9°C
Amount of heat lost = 427J
Unknown:
Mass of the block = ?
Solution:
The heat capacity of a body is the amount of heat required to change the temperature of that body by 1°C.
H = m c Ф
H is the heat capacity
m is the mass of the block
c is the specific heat capacity
Ф is the temperature change
Specific heat capacity of lead is 0.126J/g°C
m = H / m Ф
m = = 577g
Mass of the lead block is 577g
Answer:
Explanation:
From, the given information: we are not given any value for the mass, the proportionality constant and the distance
Assuming that:
the mass = 5 kg and the proportionality constant = 50 kg
the distance of the mass above the ground x(t) = 1000 m
Let's recall that:
Similarly, The equation of mption:
replacing our assumed values:
where
So, when the object hits the ground when x(t) = 1000
Then from above derived equation:
By diregarding
1000 + 0.981 = 0.981 t
1000.981 = 0.981 t
t = 1000.981/0.981
t = 1020.36 sec