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tamaranim1 [39]
3 years ago
14

you walk 6 block east, 2 blocks north, 3 blocks west and then 2 blocks north. the total distance you travel is blocks

Physics
1 answer:
Ket [755]3 years ago
4 0

Answer:

<h3> The answerI travel 13 blocks</h3>
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What is the weight of an 1000 gram mass
Reil [10]

That depends on where you weigh it.

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8 0
3 years ago
Read 2 more answers
A 0.5kg stone moving north at 4 m/s collides with a 4kg lump of clay moving west at 1 m/s. The stone becomes embedded in the cla
sergij07 [2.7K]

Answer:

The velocity of the composite body is 0.99m/s 63.43° west of north.

Explanation:

Here the law of conservation of energy says that

(1).\: \: m_1v_1cos(0)+m_2v_2cos(90^o)=(m_1+m_2)v_f cos(\theta)

(2).\: \: m_1v_1sin(0)+m_2v_2sin(90^o)=(m_1+m_2)v_f sin(\theta)

where v_f is the final velocity if the composite body, and \theta is measured from west of north.

Putting in numbers and simplifying the above equation we get:

(3).\: \: m_1v_1=(m_1+m_2)v_f cos(\theta)

(4).\: \: m_2v_2=(m_1+m_2)v_f sin(\theta)

dividing equation (4) by (3) gives

\dfrac{ m_2v_2=(m_1+m_2)v_f sin(\theta)}{ m_1v_1=(m_1+m_2)v_f cos(\theta)}

\dfrac{m_2v_2}{m_1v_1} = \dfrac{sin(\theta)}{ cos(\theta)}

(5).\: \:  tan(\theta) = \dfrac{m_2v_2}{m_1v_1}

putting in m_1 = 0.5kg, v_1 = 4m/s, m_2 = 4kg, and v_2 = 1m/s we get:

tan(\theta) = \dfrac{(4kg)(1m/s)}{(0.5kg)(4m/s)}

\boxed{\theta = 63.43^o}

Thus, the final velocity v_f we get from equation (3) is:

v_f=\dfrac{m_1v_1}{(m_1+m_2)cos(\theta)}

v_f=\dfrac{(0.5kg)(4m/s)}{(4kg+0.5kg)cos(63.43^o)}

\boxed{v_f = 0.99m/s}

Thus, the velocity of the composite body is 0.99m/s 63.43° west of north.

7 0
3 years ago
How much force is needed to stop a 100 kg football player if he decelerates at 20 m/s-2
Brut [27]
We know, f = ma
Here, m = 100 kg
a = 20 m/s²

Substitute their values, 
f = 100 * 20
f = 2000 N

In short, Your Answer would be 2000 N

Hope this helps!
7 0
2 years ago
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