<u>Answer</u>
5) b-c
6) a-b and
e-f
7) f-g
9) a-b = 0 m/s
c-d = 0.6667 m/s
e-f = 0 m/s
f-g = -3 m/s
10) b-c ⇒ The cart is acceleration.
e-f ⇒ The cart is moving backwards with a constant velocity.
<u>Explanation</u>
Answer
5) b-c
In the section b-c the cart is accelerating because the slope of the graph is changing. The gradient that represent velocity is increasing.
6) a-b and e-f
At this sections the distance is not changing at all. This can only mean that the cart is not moving. It is at rest.
7) f-g
At this section the slope is negative meaning the cart is moving back to where it came from.
9) a-b = 0 m/s
At a-b the cart is not moving. So the velocity is zero.
<u> c-d = 0.66667 m/s</u>
Velocity = distance / time
=(50-40)/(40-25)
= 10/15
= 0.6667 m/s
<u> e-f = 0 m/s</u>
At e-f the cart is not moving. So the velocity is zero.
<u> f-g = -3 m/s</u>
Velocity = distance / time
= (60-30)/(65-75)
= 30/-10
= - 3 m/s
10) b-c ⇒ The cart is acceleration.
e-f ⇒ The cart is moving backwards with a constant velocity.
Answer:
100 times
Explanation:
Since inertia is directly proportional to the mass of an object, the higher the mass the higher the inertia. In this case, 6 Kg is 100 times heavier than 0.06 Kg to imply The bowling ball has 100 times more inertia than the tennis ball because it has 100 times more mass
Answer:
20573.67N
Explanation:
Given;
mass (m) of the car = 2130kg
angle of inclination Θ = 15⁰
The normal force (F) on the car is given by
F = mgcosΘ
where g is the acceleration due to gravity.
Taking g as 10
and substituting the values of m and Θ into the equation. We have;
F = 2130 x 10 x cos 15⁰
F = 2130 x 10 x 0.9659
F = 20573.67N
Therefore the normal force on the car is 20573.67N
Answer:
The force exerted by the cart on Bonnie is - 18.0 N
Explanation:
Given;
weight of the cart, w = 195 N
Bonnie's applied force on the cart, F = 18.0 N
According to Newton's 3rd law, action and reaction are equal and opposite.
Thus, the cart will pull back at Bonnie with force of equal magnitude but in opposite direction.
The force exerted by the cart on Bonnie = - 18.0 N
Answer:
16.46 seconds.
13.46 seconds
2.67 m/s²
Explanation:
Acceleration = a = 1.35 m/s²
Final velocity = v = 80 km/h = 
Initial velocity = u = 0
Equation of motion
Time taken to accelerate to top speed is 16.46 seconds.
Acceleration = a = -1.65 m/s²
Initial velocity = u = 80 km/h=
Final velocity = v = 0
Time taken to stop the train from top speed is 13.46 seconds
Initial velocity = u = 80 km/h=
Time taken = t = 8.3 s
Final velocity = v = 0
Emergency deceleration is 2.67 m/s²
