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Ne4ueva [31]
3 years ago
15

Use the graph below to answer the following question: if average acceleration is calculated using the equation, “ change in velo

city / change in time,” what is an abject acceleration at 4s? Be sure to include units in your math work and in your final answer.

Physics
1 answer:
sergiy2304 [10]3 years ago
6 0

Answer:

a=9\ cm/s^2

Explanation:

<u>Average Acceleration </u>

Acceleration is a physical magnitude defined as the change of velocity over time. When we have experimental data, we can compute it by calculating the slope of the line in velocity vs time graph.

Note: <em>We cannot see if the time axis is numbered in increments of 1 second, and we'll assume that. </em>

When t_2=4\ sec, the graph shows a value of v_2=36\ cm/s

When t_1=0\ sec, the object is at rest, v_1=0

We compute the average acceleration as

\displaystyle a=\frac{v_2-v_1}{t_2-t_1}

\displaystyle a=\frac{36\ cm/s-0\ cm/s}{4\ sec-0\ sec}

\displaystyle a=\frac{36\ cm/s}{4\ s}

\boxed{a=9\ cm/s^2}

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b) a = -k / m x , c) d²x / dt² = - A w² cos (wt+Ф) , d) and e)  T = 2π √m / k

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a) see free body diagram in the attachment

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          Fe = m a

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c) the acceleration is

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        a = d²x / dt² = - A w² cos (wt+Ф)

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We call

       w² = k / m

e) substitute to find w

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      w² = k / m

Angular velocity and frequency are related

       w = 2π f

       f = 1 / T

       

 We substitute

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      T = 2π √m / k

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h) acceleration is

       a = - A w² cos (wt+Ф)

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