Answer:
The disintegrations is .
Explanation:
Given that,
Weight of sample = 200 g
Decay constant
We need to calculate the disintegrations
Using formula of disintegrations
Where, = decay constant
N = number of atoms present at time t
Put the value into the formula
Hence, The disintegrations is .
Answer:
6.7*10^8 mi/hr
Explanation:
(3*10^8 m)/1s * (3600 s)/ 1 hr * (1 mi)/ 1609 m
6.7*10^8 mi/hr
A half-life is how long it takes for half of an element's particles to decay.
In 0 half-lives there will be 100% or 4/4 of the element left
After 1 half-life there will be 50% or 2/4 of the element's original particles left
After 2 half lives there will be 25% or 1/4 of the element's original particles left.
Since there is only 1/4 the original amount of the radium-226, we know that 2 half-lives have passed. Simply divide 3200 by 2 to get the time of 1 half-life.
3200/2 = 1,600 years is the half life of radium-226.
I really hope this helps you =)
Without a picture of the situation, we don't know the relationship
between angle-G, g, k, and 'h'. We don't even know for sure
whether 'h' is on the same planet as the other things. No answer
is possible without seeing the picture.