"Rubble pile" asteroids have low average densities due to being up to 50% empty space inside.

What type of fingerprints is invisible to the naked eye?

luda_lava [24]

Well latent fingerprints are made of oil and sweat and generally materials that you can't see very easily, so it should be that.

Hope this helps :D

3 0

4 years ago

The acceleration due to gravity near Earth ... Select one: a. varies inversely with the distance from the center of Earth. by. v

vladimir1956 [14]

Answer:

b. varies inversely with the square of the distance from the center of Earth.

Explanation:

Comparing the Newton's law of universal gravitation and second law of motion;

from Newton's second law of motion,

F = ma ............. 1

from New ton's law of universal gravitation,

F = $\frac{GMm}{r^{2} }$ ........... 2

Equating 1 and 2, we have;

mg = $\frac{GMm}{r^{2} }$

g = $\frac{GM}{r^{2} }$

Therefore, the acceleration due to gravity near Earth, g, is inversely proportional to the square of the distance from the center of Earth.

7 0

3 years ago

The speed of sound waves

neonofarm [45]

B. Is faster in solids than liquids would be the correct answer because the molecules in solids are much closer and can pass along energy faster and more effectively.

4 0

3 years ago

An automobile battery has an emf of 12.6 V and an internal resistance of 0.0600 . The headlights together present equivalent res

murzikaleks [220]

Answer:

(a) $V=11.86\ V$

(b) $V=9.76\ V$

Explanation:

<u>Electric Circuits</u>

Suppose we have a resistive-only electric circuit. The relation between the current I and the voltage V in a resistance R is given by the Ohm's law:

$V=R.I$

(a) The electromagnetic force of the battery is $\varepsilon =12.6\ V$ and its internal resistance is $R_i=0.06\ \Omega$ . Knowing the equivalent resistance of the headlights is $R_e=5.2\ \Omega$ , we can compute the current of the circuit by using the Kirchhoffs Voltage Law or KVL:

$\varepsilon=i.R_i+i.R_e=i.(R_i+R_e)$

Solving for i

$\displaystyle i=\frac{\varepsilon}{ R_i+R_e}=\frac{12}{0.06+5.2}=2.28\ A$

i=2.28\ A

The potential difference across the headlight bulbs is

$V=\varepsilon -i.R_i=12\ V-2.28\ A\cdot 0.06\ \Omega=11.86\ V$

$V=11.86\ V$

(b) If the starter motor is operated, taking an additional 35 Amp from the battery, then the total load current is 2.28 A + 35 A = 37.28 A. Thus the output voltage of the battery, that is the voltage that the bulbs have is

$V=\varepsilon -i.R_i=12\ V-37.28\ A\cdot 0.06\ \Omega=9.76\ V$

5 0

3 years ago

An unusual fog that is denser than air begins to fill a room. Should the people in the room walk out or crwl out? The people sho

horsena [70]

Walk out. If it's denser than air, it'll settle to the bottom

8 0

3 years ago