I believe its the law of inertia
Since the frequency of sound in a medium is constant, therefore, the concert-goers would hear the low notes and high notes at the same time.
<h3>What is a dispersive medium?</h3>
A dispersive medium is a medium which spreads out or disperses a substance passing through it.
Since CO2 is a dispersive medium, it means sound waves passing through it would be dispersed based on wavelength.
The note of a sound depends on its frequency, the higher the frequency, the higher the note.
Frequency of sound is constant, therefore, the concert-goers would hear the low notes and high notes at the same time.
Learn more about dispersion of sound at: brainly.com/question/781734
Answer:
The puck moves a vertical height of 2.6 cm before stopping
Explanation:
As the puck is accelerated by the spring, the kinetic energy of the puck equals the elastic potential energy of the spring.
So, 1/2mv² = 1/2kx² where m = mass of puck = 39.2 g = 0.0392 g, v = velocity of puck, k = spring constant = 59 N/m and x = compression of spring = 1.3 cm = 0.013 cm.
Now, since the puck has an initial velocity, v before it slides up the inclined surface, its loss in kinetic energy equals its gain in potential energy before it stops. So
1/2mv² = mgh where h = vertical height puck moves and g = acceleration due to gravity = 9.8 m/s².
Substituting the kinetic energy of the puck for the potential energy of the spring, we have
1/2kx² = mgh
h = kx²/2mg
= 59 N/m × (0.013 m)²/(0.0392 kg × 9.8 m/s²)
= 0.009971 Nm/0.38416 N
= 0.0259 m
= 2.59 cm
≅ 2.6 cm
So the puck moves a vertical height of 2.6 cm before stopping
Answer:
λ = 5.4196 10⁻⁷m, λ = 541.96 nm this is green ligh
Explanation:
The photoelectric effect was explained by Eintein assuming that the light was made up of particles called photons and these collided with the electrons taking them out of the material.
K = h f -Ф
where K is the kinetic energy of the ejected electrons, hf is the energy of the light quanta and fi is the work function of the material.
The speed of light is related to wavelength and frequency
c = λ / f
f = c /λ
we substitute
K = h c / λ - Φ
for the case that they ask us the kinetic energy of the electons is zero (K = 0)
h c / λ = Ф
λ = h c / Ф
we calculate
λ = 6.63 10⁻³⁴ 3 10⁸ / 3.67 10⁻¹⁸
λ = 5.4196 10⁻⁷m
let's take nm
lam = 541.96 nm
this is green light
Answer:
a
The speed of wave is ![v_1 = 129.1 \ m/s](https://tex.z-dn.net/?f=v_1%20%20%3D%20129.1%20%5C%20m%2Fs)
b
The new speed of the two waves is ![v = 129.1 \ m/s](https://tex.z-dn.net/?f=v%20%3D%20%20129.1%20%5C%20m%2Fs)
Explanation:
From the question we are told that
The mass of the string is ![m = 60 \ g = 60 *10^{-3} \ kg](https://tex.z-dn.net/?f=m%20%20%3D%20%2060%20%5C%20g%20%20%3D%20%2060%20%2A10%5E%7B-3%7D%20%5C%20kg)
The length is ![l = 2.0 \ m](https://tex.z-dn.net/?f=l%20%20%3D%20%202.0%20%5C%20m)
The tension is ![T = 500 \ N](https://tex.z-dn.net/?f=T%20%20%3D%20500%20%5C%20N)
Now the velocity of the first wave is mathematically represented as
![v_1 = \sqrt{ \frac{T}{\mu} }](https://tex.z-dn.net/?f=v_1%20%20%3D%20%5Csqrt%7B%20%5Cfrac%7BT%7D%7B%5Cmu%7D%20%7D)
Where
is the linear density which is mathematically represented as
![\mu = \frac{m}{l}](https://tex.z-dn.net/?f=%5Cmu%20%20%3D%20%20%5Cfrac%7Bm%7D%7Bl%7D)
substituting values
![\mu = \frac{ 60 *10^{-3}}{2.0 }](https://tex.z-dn.net/?f=%5Cmu%20%20%3D%20%20%5Cfrac%7B%2060%20%2A10%5E%7B-3%7D%7D%7B2.0%20%7D)
![\mu = 0.03\ kg/m](https://tex.z-dn.net/?f=%5Cmu%20%20%3D%20%200.03%5C%20kg%2Fm)
So
![v_1 = \sqrt{ \frac{500}{0.03} }](https://tex.z-dn.net/?f=v_1%20%20%3D%20%5Csqrt%7B%20%5Cfrac%7B500%7D%7B0.03%7D%20%7D)
![v_1 = 129.1 \ m/s](https://tex.z-dn.net/?f=v_1%20%20%3D%20129.1%20%5C%20m%2Fs)
Now given that the Tension, mass and length are constant the velocity of the second wave will same as that of first wave (reference PHYS 1100 )