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hoa [83]
3 years ago
9

3. What are the forces present on the rope?​

Physics
1 answer:
irina1246 [14]3 years ago
7 0

Answer:

The pulling force that acts along a stretched flexible connector, such as a rope or cable, is called tension, T. When a rope supports the weight of an object that is at rest, the tension in the rope is equal to the weight of the object: T = mg.

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How long would it take a 4,560 watt motor to raise a 166 kg piano to an apartment window
IrinaK [193]

Answer:

Explanation:

We need the power equation here:

P = W/t where W is work and is defined as

W = F*displacement.

Force is a measure in Newtons, which is also weight. We have the mass of the piano, but we need to find the weight:

w = mg so

w = 166(9.8) so

w = 1600N, rounded to the correct number of sig dig. We use that now in the power equation:

4560=\frac{(1600)(15)}{t} and isolating the unknown:

t=\frac{(1600)(15)}{4560} so

t = 5.3 seconds

8 0
3 years ago
Through what potential difference would you need to accelerate an alpha particle, starting from rest, so that it will just reach
Svetlanka [38]

Answer:

\Delta V    = 1.8 \times 10^7 V

Explanation:

GIVEN

diameter = 15 fm  =15 \times 10^{-15}m

we use here energy conservation

K_{i}+U_{i} =K_{f}+U_{f}

there will be some initial kinetic  energy but after collision kinetic energy will zero

K_{i} + 0 = 0 + \frac{1}{4 \pi \epsilon _{0}} \frac{(2e)(92e)}{7.5 \times 10^{-15}}

on solving these equations we get kinetic energy initial

KE_{i} = 5.65\times 10 ^{-12} \times \frac  {1 eV}{1.6 \times 10^{-19}}

KE_{i} = 35.33 J ..............(i)

That is, the alpha particle must be fired with 35.33 MeV of kinetic energy. An alpha particle with charge q = 2  e

and gains kinetic energy K  =e∆V  ..........(ii)

 by accelerating through a potential difference ∆V

Thus the alpha particle will

just reach the {238}_U nucleus after being accelerated through a potential difference  ∆V

equating (i) and second equation we get

e∆V  = 35.33 Me V

\Delta V = \frac{35.33}{2}  MV\\\Delta V    = 1.8 \times 10^7 V

7 0
3 years ago
Which of the following is NOT an important function of the components of the muscular system?
polet [3.4K]

D. Vitamin storage.            

3 0
3 years ago
Read 2 more answers
Suppose that the moment of inertia of a skater with arms out and one leg extended is 3.0 kg⋅m2 and for arms and legs in is 0.90
babymother [125]

Answer:

Her angular speed (in rev/s) when her arms and one leg open outward is 1.56\frac{rev}{s}

Explanation:

Initial moment of inertia when arms and legs in is I_i=0.90 kg.m^{2}

Final moment of inertia when her arms and on leg open outward, I_f=3.0 kg.m^{2}

Initial angular speed w_i=5.2\frac{rev}{s}

Let the final angular speed be w_f

Since external torque on her is zero so we can apply conservation of angular momentum

\therefore L_f=L_i

=>I_fw_f=I_iw_i

=>w_f=\frac{I_iw_i}{I_f}=\frac{0.9\times5.2 }{3.0}\frac{rev}{s}=1.56\frac{rev}{s}

Thus her angular speed (in rev/s) when her arms and one leg open outward is 1.56\frac{rev}{s}

7 0
3 years ago
Acceleration is calculated from position and time. Agree Disagree Explain why you voted the way you did.
Bas_tet [7]

Answer:

Acceleration is the derivative of velocity with time, but velocity is itself the derivative of position with time.

Explanation:

3 0
2 years ago
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