Answer:
t = (p - 1/2)/3
Step-by-step explanation:
p = 4t + 1/2 - t
combine like terms:
p = 3t + 1/2
subtract 1/2 from each side of the equation:
3t = p - 1/2
divide both sides by 3:
t = (p - 1/2)/3
We know that
speed=distance/time
solve for time
time=distance/speed
in this problem
<span>Marco runs at a rate of 6 miles per hour.
</span><span>Fernando funs at a rate of 7.2 miles per hour
Difference=7.2-6=1.2 miles/hour
so
speed=1.2 miles/hour
distance=0.3 miles
time=?
</span>time=distance/speed-----> 0.3/1.2-----> 0.25 hour-----> 0.25*60=15 minutes
<span>
the answer is
0.25 hour (15 minutes)
Alternative Method
Let
x---------> Fernando's distance when Marco is 0.3 miles apart
</span>Fernando funs at a rate of 7.2 miles per hour
<span>for distance =x
time=x/7.2------> equation 1
</span>Marco runs at a rate of 6 miles per hour.
for distance=x-0.30
time=(x-0.30)/6------> equation 2
equate equation 1 and equation 2
7.2*(x-0.3)=6x-----> 7.2x-2.16=6x
7.2x-6x=2.16------> x=2.16/1.2-------> x=1.8 miles
time=x/7.2-----1.8/7.2=0.25 hour
412-217
195 units
Just subtract them and that would be the distance I’m pretty sure
Answer:
-1/4
Step-by-step explanation:
2-1 over -3-1 = 1/-4
1. You convert all the numbers into decimals.
a. For 8 1/9 you multiply 8x9 and add the numerator which in this case is one, so the equation would be 8x9=72 then 72+1= 73
b. For 81/10 I used a calculator for accuracy and I just divided 81 by 10 because the fraction line can also be used as a division sign. For this I got 8.1
2. Now I looked at all the numbers I had including the fractions I converted to decimals... 8.115, 8.55, 73, and 8.1
3. Lastly, I put the numbers in order from least to greatest: 8.1, 8.115, 8.55, and 73
4. In order to figure out which one is the smallest and largest, I just added zeros on the end of the numbers so they would all be the same: 8.1-->8.100, 8.115 I kept the same because it already had 3 decimal places, 8.55--> 8.550, and 73--> 73.000
5. Then i could tell which number was the largest by the decimal place numbers.
**Hope this was helpful... It's kind of hard to explain online but hopefully you have a better understanding of how to do it!**
