Answer:
D. Force of attraction between one atom and another atom
Explanation:
Chemical bond is the force of attraction between the atoms, molecules or ions due to which different types of chemical compounds are formed. Based on the types of attractions the bonds have been categorized in the following three categories-
- Ionic bonds - there is electrostatic force of attraction between the charged ions
- Covalent bonds - mutual sharing of the electrons occur
- Metallic bond - here many detached electrons are shared between more than two positively charged ions.
Answer: gravity
Explanation:
Answer:
2 KOH → H₂O + K₂O
Explanation:
When KOH descomposes in potassium oxide, K₂O and water, H₂O.
The unbalanced equation is:
KOH → H₂O + K₂O
As you can see, 2 hydrogen, potassium and oxygen atoms are produced, to balance this equation we can write:
2 KOH → H₂O + K₂O
This is the balanced equation because 2 atoms of K, H and O are in reactants and products
Answer:
A chemical change occured, so even if Cash heats it, the white solid will remain.
Explanation:
CH3CH2CH2CH3 < CH3CH2CHO < CH3CHOHCH3
Explanation:
Boiling point trend of Butane, Propan-1-ol and Propanal.
Butane is a member of the CnH2n+2 homologous series is an alkane. Alkanes have C-H and C-C bonds which have Van der waals dispersion forces which are temporary dipole-dipole forces (forces caused by the electron movement in a corner of the atom). This bond is weak but increases as the carbon chain/molecule increases.
In Propan-1-ol(Primaryalcohol), there is a hydrogen bond present in the -OH group. Hydrogen bond is caused by the attraction of hydrogen to a highly electronegative element like Cl-, O- etc. This bond is stronger than dispersion forces because of the relative energy required to break the hydrogen bond. Alcohols (CnH2n+1OH) also experience van der waals dispersion forces on its C-C chain and C-H so as the Carbon chain increases the boiling point increases in the homologous series.
Propanal which is an Aldehyde (Alkanal) with the general formula CnH2n+1CHO. This molecule has a C-O, C-C and C-H bonds only. If you notice, the Oxygen is not bonded to the Hydrogen so there is no hydrogen bond but the C-O bond has a permanent dipole-dipole force caused by the electronegativity of oxygen which is bonded to carbon. It also has van der waals dispersion forces caused by the C-C and C-H as the carbon chain increases down the homologous series. The permanent dipole-dipole forces are not as easy to break as van der waals forces.
In conclusion, the hydrogen bonds present in alcohols are stronger than the permanent dipole-dipole bonds in the aldehyde and the van der waals forces in alkanes (irrespective of the carbon chain in Butane). So Butane < Propanal < Propan-1-ol