Which is a TRUE statement about the transformation shown?

Mathematics

2 answers:

alekssr [168]2 years ago

4 0

B because it’s moving on the x axis

Darina [25.2K]2 years ago

3 0

Answer:

D. I'm guessing

Step-by-step explanation:

because its going up and down so thats vertical..

You might be interested in

Find f(2) if f(x) = (x + 1)2. 1. 9 2. 6 3. 5

kolezko [41]

Answer: f(2) = 6

Step-by-step explanation: In this problem, we are given the function

f (x) = (x + 1) 2 and we are asked to find f(2). In other words, if we put an "x" into our function, we get a (x + 1) 2 out.

f we put a 2 into the function, we get f(2) = (2 + 1) 2 out. Now all we have to do is simplify on the right side.

2 + 1 gives us 3 and if we multiply 3 by 2, we get a product of 6.

Therefore, f(2) is 6.

7 0

3 years ago

Four teachers by 10 origami books and 100 packs of origami paper for their classrooms they will share the cost of the Items equa

Tamiku [17]

$24 times 10 is $240 and $6 times 100 is $600 so 240+$600 is $840 then $840 devided by 4 is $210.

3 0

3 years ago

When the sum of 5 and three times a positive number is subtracted from the square of the number, 0 results. Find the number.

Juliette [100K]

$x-the\ number\\\\x^2-(5+3x)=0\\\\x^2-5-3x=0\\\\x^2-3x-5=0$

$Use\ the\ quadratic\ formula:\\a^2x+bx+c=0\\\\\Delta=b^2-4ac\\\\if\ \Delta > 0\ then\ x_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\if\ \Delta=0\ then\ x_0=\dfrac{-b}{2a}\\\\if\ \Delta < 0\ then\ no\ solution$

$x^2-3x-5=0\\\\a=1;\ b=-3;\ c=-5\\\\\Delta=(-3)^2-4\cdot1\cdot(-5)+3+20=29 \ \textgreater \ 0\\\\\sqrt\Delta=\sqrt{29}\\\\x_1=\dfrac{3-\sqrt{29}}{2\cdot1}=\dfrac{3-\sqrt{29}}{2} \ \textless \ 0\\\\x_2=\dfrac{3+\sqrt{29}}{2\cdot1}=\dfrac{3+\sqrt{29}}{2} \ \textgreater \ 0$

$Answer:\ \boxed{x=\dfrac{3+\sqrt{29}}{2}}$