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erastova [34]
3 years ago
13

Suppose there was a release of 1 mole of Alpha emission particle and 1 mole of Beta emission particles and both particles are ac

celerated to 20.50 MeV. What is the total energy in kJ/nuclei? Hint: 1 MeV = 1 x 106 eV and 1 eV = 1.602 X 10-19 J and 1 kJ = 1000 J, and finally in 1 mole there are Avogadro's number of particles which is 6.02214 x 1023 particles/mole. Report your answer in scientific notation to 2 decimal places for example 1.23 x 10-4 would be entered as 1.23 E-4.
238 92 U → 4 2 He + 234 90 Th and then 234 90 Th → 0
-1e + 234 91 Pa
Chemistry
1 answer:
riadik2000 [5.3K]3 years ago
7 0

Explanation:

translate the following word equation in the form of balance come alive with your number is aluminium + hydrochloric acid and Aluminium chloride + nitrogen

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An element has an atomic number of 18 and an atomic mass of 40. The number of neutrons in the nucleus of an atom of this element
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A 8.65-L container holds a mixture of two gases at 11 °C. The partial pressures of gas A and gas B, respectively, are 0.205 atm
Vsevolod [243]

 The  total pressure  = 1.402 atm


<u><em>calculation</em></u>

Total  pressure = partial  pressure  of gas A + partial pressure of gas B +  partial pressure  of third gas

partial  pressure  of gas A= 0.205 atm

Partial pressure of gas B =0.658 atm


partial pressure for third gas is calculated using ideal  gas equation

that is PV=nRT   where,

p(pressure)=? atm

V(volume) = 8.65 L

n(moles)= 0.200 moles

R(gas constant)=0.0821 L.atm/mol.k

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make  p the subject of the formula by  diving both side by V

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p = [(0.200 moles x 0.0821 L.atm/mol.K x 284 K)/8.65L)] =0.539 atm



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3 years ago
If I have a 50.0 liter container that holds 45 moles of gas at a
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The Answer Is B Because You Have To Divide The 9
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