A hydrated substance will decrease in mass when heated since the water is being boiled away.
I hope this helps. Let me know if anything is unclear.
Answer:
How many atoms are in 6.5 moles of zinc? 6.5 moles. 6.02 x 10. 23 atoms = 3.9 x 10. 24 ... 55.8g. 1 mole. 6. What is the mass of 0.250 moles of aluminum?
Explanation:
hope this help rate me
Answer:
I dont know if this is correct.. but maybe in the tool row, put graduated cylinder because you use graduated cylinders to measure water and for units put milliliters or liters?? Sorry if this isnt correct i wouldnt know what else to put !
Explanation:
We convert the masses of our reactants to moles and use the stoichiometric coefficients to determine which one of our reactants will be limiting.
Dividing the mass of each reactant by its molar mass:
(10 g C2H6)(30.069 g/mol) = 0.3326 mol C2H6
(10 g O2)(31.999 g/mol) = 0.3125 mol O2.
Every 2 moles of C2H6 react with 7 moles of O2. So the number of moles of O2 needed to react completely with 0.3326 mol C2H6 would be (0.3326)(7/2) = 1.164 mol O2. That is far more than the number of moles of O2 that we are given: 0.3125 moles. Thus, O2 is our limiting reactant.
Since O2 is the limiting reactant, its quantity will determine how much of each product is formed. We are asked to find the number of grams (the mass) of H2O produced. The molar ratio between H2O and O2 per the balanced equation is 6:7. That is, for every 6 moles of H2O that is produced, 7 moles of O2 is used up (intuitively, then, the number of moles of H2O produced should be less than the number of moles of O2 consumed).
So, the number of moles of H2O produced would be (0.3125 mol O2)(6 mol H2O/7 mol O2) = 0.2679 mol H2O. We multiply by the molar mass of H2O to convert moles to mass: (0.2679 mol H2O)(18.0153 g/mol) = 4.826 g H2O.
Given 10 grams of C2H6 and 10 grams of O2, 4.826 g of H2O are produced.
Answer:
The equilibrium concentration of HCl is 0.01707 M.
Explanation:
Equilibrium constant of the reaction = 
Moles of ammonium chloride = 0.573 mol
Concentration of ammonium chloride = 
Initial: 0.573 0 0
At eq'm: (0.573-x) x x
We are given:
![[NH_4Cl]_{eq}=(0.573-x)](https://tex.z-dn.net/?f=%5BNH_4Cl%5D_%7Beq%7D%3D%280.573-x%29)
![[HCl]_{eq}=x](https://tex.z-dn.net/?f=%5BHCl%5D_%7Beq%7D%3Dx)
![[NH_3]_{eq}=x](https://tex.z-dn.net/?f=%5BNH_3%5D_%7Beq%7D%3Dx)
Calculating for 'x'. we get:
The expression of 
for above reaction follows:
![K_c=\frac{[HCl][NH_3]}{[NH_4Cl]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BHCl%5D%5BNH_3%5D%7D%7B%5BNH_4Cl%5D%7D)
Putting values in above equation, we get:
On solving this quadratic equation we get:
x = 0.01707 M
The equilibrium concentration of HCl is 0.01707 M.
