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3 years ago

How many joules of heat are lost when 150.0 g of steam are cooled from 124. C to 86 C?

Chemistry

1 answer:

Alinara [238K]3 years ago

6 0

The amount of joules of heat that are lost when 150.0 g of steam are cooled from 124 °c to 86 °c is = -11343 joules

calculation

heat(Q) = mass(m) x specific heat capacity(C) x change in temperature (ΔT)

where,

Q=? joules

M=150.0 g

C for steam = 1.99 j/g/°c

ΔT= 86°c-124°c = -38°c

Q is therefore = 150.0 g x 1.99 j/g/°c x -38°c =-11343 joules

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Expression for rate law for first observation:

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Expression for rate law for second observation:

$2.9\times 10^{-4}=k(0.164)^a(0.45)^b$ ....(2)

Expression for rate law for third observation:

$1.4\times 10^{-4}=k(0.082)^a(0.45)^b$ ....(3)

Expression for rate law for fourth observation:

$4.8\times 10^{-5}=k(0.246)^a(0.15)^b$ ....(4)

Dividing 2 from 1, we get:

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