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puteri [66]
2 years ago
8

Write the equation of the circle centered at (4, - 9) with diameter 16. HELP A GIRL OUT

Mathematics
1 answer:
iragen [17]2 years ago
4 0

Answer:

16= (x-4)^2 +(y+9)^2

Step-by-step explanation:

hey! The formula for the equation of a circle is r^2= (x-h)^2 + (y-k)^2

r= the radius (in your case you have the diameter so you do not need to square it)

(h,k)= is the center coordinates, so your center coordinate would be (4, -9). You now have your h (h=4) and your k (k=-9) so you can plug it in the formula! :)

a nice rating would help out

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ANSWER:

\:D.\text{ }f^{-1}\left(x\right)=\left(x+4\right)^2;x\ge-4

STEP-BY-STEP EXPLANATION:

We have the following equation:

f(x)=\sqrt{x}-4

The inverse is the following (we calculate it by replacing f(x) by x and x by f(x)):

\begin{gathered} x=\sqrt{f^{-1}(x)}-4 \\  \\ \sqrt{f^{-1}(x)}=x+4 \\  \\ f^{-1}(x)=(x+4)^2 \end{gathered}

The domain would be the range of the original equation, and it would be the range of values that f(x) could take, which was from -4 to positive infinity, that is, f(x) ≥ -4.

Therefore, the domain is x ≥ -4.

So the correct answer is D.

\:f^{-1}\left(x\right)=\left(x+4\right)^2;x\ge -4

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Step-by-step explanation:

Hi, the answer is lacking the last part:

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Step-by-step explanation:

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