Question

Does anyone know how to do this

Answer 1

Answer:

The solution is B

Step-by-step explanation:

$x + 5 \geqslant 1 \\ x \geqslant 1 - 5 \\ x \geqslant - 4$

then:

$x - 7 < - 3 \\ x < - 3 + 7 \\ x < 4$

therefore, interval [limits] of x:

$- 4 \leqslant x < 4$