Answer:
15m/s²
Explanation:
According to Newton's second law;
Force = mass * acceleration
Given
Force = 1.5N
mass = 0.10kg
Required
acceleration
Substitute into the expression;
1.5 = 0.1a
a = 1.5/0.1
a = 15m/s²
Hence the acceleration that the puck move across the air table is 15m/s²
Answer:
a) Em= K +U, b) Em= K
Explanation:
The system in this case is formed by the mobilizes and the hill.
Let's write the expressions correctly and completely.
a) When the car moves in the path, the mechanical energy is the siua of the kinetic energy of the car and the potential energy of the car when going up the hill.
Em = K + U
be) when the car moves in the flat part all the mechanical energy is formed by its kinetic energy that is calculated with the mass and speed of the car
Em = K
c) When the car goes up the hill the energy the mechanical energy is conserved, but part of the kinetic energy is transformed into potential energy.
Compass and metal detector are the practical applications of magnetism.
<h3> Which two activities are practical applications of magnetism?</h3>
Using a compass to find your way to a campsite and a metal detector to find buried iron objects are the practical applications of magnetism because in these tools magnet is used. Without magnet, they can't perform their function.
So we can conclude that compass and metal detector are the practical applications of magnetism.
Learn more about magnet here: brainly.com/question/14997726
#SPJ1
Answer:
The atoms that contain an unstable combination of neutrons and protons, or excess energy in their nucleus
The distance between two consecutive nodes and the amplitude after 0.56s are m/2 and 1.75×10^(-4) m respectively.
<h3>What's the distance between consecutive nodes of the displacement of air molecules?</h3>
- Wavelength is the distance between two consecutive nodes or toughs or crests or anti-nodes.
- So, distance between consecutive nodes = wavelength = 2π÷k
= 2π/(4π÷m)
= m/2
<h3>What's the amplitude after 0.56s of the displacement of air molecules?</h3>
Displacement after 0.56 s = 0.008×cos(50π×0.56s)
=1.75×10^(-4) m
Thus, we can conclude that the distance between consecutive nodes and displacement after 0.56 s are m/2 and 1.75×10^(-4) m respectively.
Disclaimer: The question was given incomplete on the portal. Here is the complete question.
Question: The particle displacement y of air molecules due to a sound wave is given by y=0.008coswtsinkz where k=4π÷m and w=50π rads/s.
Calculate:
I) the distance between 2 consecutive nodes
ii) the amplitude after 0.565s
Learn more about the wavelength here:
brainly.com/question/10750459
#SPJ1