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love history [14]
4 years ago
6

A large mass collides with a stationary, smaller mass. How will the masses behave if the collision is inelastic?

Physics
1 answer:
iragen [17]4 years ago
3 0
Logically both masses will collide and well make a reaction. first of all depending on the small mass it will either merge or unite with the big mass or it will bounce away from it . if this happen it will make a reaction that will affect both masses. Hope this helps if it is incorrect please let me know :) 

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You pull down on a rope to raise a flag on a flag pole which describes why the rope and the flag pole act as a machine
ikadub [295]

Answer: A-they change the direction of the forces

Explanation:

Any device which makes our work simpler is known as a machine. A machine may increase the amount of output force which is determined by its mechanical advantage or a machine changes the direction of the force.

In the given situation the input force acts in the downward direction to pull the rope. The output force acts on the flag being pulled upwards at the other end. Thus, the direction of the forces varies. Correct option is A.

3 0
4 years ago
Richard Julius once made a model plane that could travel a max speed of 110 m/s. Suppose the plane was held in a circular path b
hjlf

Answer:

85.8 m/s

Explanation:

We know that the length of the circular path, L the plane travels is

L = rθ where r = radius of path and θ = angle covered

Now,its speed , v = dL/dt = drθ/dt = rdθ/dt + θdr/dt

where dθ/dt = ω = angular speed = v'/r where v' = maximum speed of plane and r = radius of circular path

Now, from θ = θ₀ + ωt where θ₀ = 0 rad, ω = angular speed  and t = time,

θ = θ₀ + ωt = 0 + ωt = ωt

So, v = rdθ/dt + θdr/dt

v = rω + ωtdr/dt

v = (r + tdr/dt)ω

v = (r + tdr/dt)v'/r

v = v' + tv'/r(dr/dt)

v = v'[1 + t(dr/dt)/r]

Given that v' = 110 m/s, t = 33.0s, r = 120 m and dr/dt = rate at which line is shortened = -0.80 m/s (negative since it is decreasing)

So, v = 110 m/s[1 + 33.0 s(-0.80 m/s)/120 m]

v = 110 m/s[1 + 11.0 s(-0.80 m/s)/40 m]

v = 110 m/s[1 + 11.0 s(-0.02/s)]

v = 110 m/s[1 - 0.22]

v = 110 m/s(0.78)

v = 85.8 m/s

8 0
3 years ago
A. In the building there are 133 steps from the ground floor to the sixth floor.
faust18 [17]

(a) The work done by the person is 18.83465 kJ.

(b) The average power performed by the person during the walk is 51.4 W.

(c) The amount of food calories burnt is 4.5 Cal.

<h3>Work done by the person</h3>

The work done by the person is calculated as follows;

W = Fd

W = mgh

W = (89.2 x 9.8) x (0.162 x 133)

W = 18,834.65 J

W = 18.83465 kJ

<h3>Average power of the person</h3>

P = Fv

where;

  • v is velocity

v = (d)/t

v = (133 x 0.162)/(6 x 60   +  6)

v = (133 x 0.162)/(366)

v = 0.0588 m/s

P = (89.2 x 9.8) x 0.0588

P = 51.4 W

<h3>Amount of food calories burnt</h3>

4.1868 kJ = 1 Cal

18.83465 kJ = ?

= 4.5 Cal

Learn more about work done here: brainly.com/question/8119756

#SPJ1

7 0
2 years ago
A force of 30 N is applied tangentially to the rim of a solid disk of radius 0.14 m. The disk rotates about an axis through its
sammy [17]

Answer: 3.27kg

Explanation:

Inertia can be said to be the resistance of an object to a change in its motion. This includes a change in its direction. An object will stay still or keep moving at the same speed and in a straight line, except it is acted upon by an unbalanced external force.

Given F = 30N

r = 0.14m

a = 130rad/s²

Then, T = Fr

T = 30*0.14

T = 4.2Nm

Also, T = inertia * acceleration

Inertia = 4.2/a

Inertia = 4.2/130

Inertia = 0.032

Also, inertia = mr²/2

0.032 = m * (0.14²)/2

0.032 = m * 0.0098

m = 0.032/0.0098

m = 3.27kg

4 0
3 years ago
Using a refracting telescope, you observe the planet Mars when it is 2.11 × 10 11 m 2.11×1011 m from Earth. The diameter of the
Norma-Jean [14]

Answer:

y = 150 Km

Explanation:

given,                                                      

Distance of the planet Mars from earth D = 2.11 × 10¹¹ m          

The diameter of the telescope's objective lens d = 0.949 m      

The wavelength of light λ = 553 nm            

                                        = 553 x 10⁻⁹ m            

resolution of the telescope = ?                          

     y = \dfrac{1.22\lambda\ D}{d}          

     y = \dfrac{1.22\times 553\times 10^{-9}\times 2.11 \times 10^{11}}{0.949}                                          

           y = 150003 m                          

          y = 150 Km                          

the minimum feature size is equal to y = 150 Km

8 0
3 years ago
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