If this trapezoid is moved through the

Mathematics

1 answer:

miskamm [114]3 years ago

7 0

Hi! I'm happy to help!

We can see that A's coordinates currently are -6 for x and 2 for y.

When we move x+3, it moves the x coordinate to the right 3 units. This changes it from -6 to -3. When we move y -2, we move the y coordinate down 2 units. This changes it from 2, to 0.

To sum it up: The final coordinates of A will be -3 for x and 0 for y, also written as (-3,0).

I hope this was helpful, keep learning! :D

You might be interested in

Simplify the expression. -5+i/2i

Lostsunrise [7]

Answer:

$\rm - \dfrac{11}{2}$

Step-by-step explanation:

$\rm Simplify \: the \: following: \\ \rm \longrightarrow - 5 + \dfrac{i}{2} i \\ \\ \rm Combine \: powers. \\ \rm \dfrac{i \times i}{2} = \dfrac{i^{1 + 1}}{2}: \\ \rm \longrightarrow - 5 + \dfrac{i^{1 + 1}}{2} \\ \\ \rm 1 + 1 = 2: \\ \rm \longrightarrow - 5 + \dfrac{i^2}{2} \\ \\ \rm i^2 = -1: \\ \rm \longrightarrow - 5 + \dfrac{( - 1)}{2} \\ \\ \rm \longrightarrow - 5 - \dfrac{1}{2} \\ \\ \rm Put \: - 5 - \dfrac{1}{2} \: over \: the \: common \: denominator \: 2. \\ \rm - 5 - \dfrac{1}{2} = \dfrac{2( - 5)}{2} - \dfrac{1}{2} : \\ \rm \longrightarrow \dfrac{ - 5 \times 2}{2} - \dfrac{1}{2} \\ \\ \rm 2 (-5) = -10: \\ \rm \longrightarrow \dfrac{ - 10}{2} - \dfrac{1}{2} \\ \\ \rm \dfrac{ - 10}{2} - \dfrac{1}{2} = \dfrac{ - 10 - 1}{2} : \\ \rm \longrightarrow \dfrac{ - 10 - 1}{2} \\ \\ \rm -10 - 1 = -11: \\ \rm \longrightarrow - \dfrac{11}{2}$