The molality of the solution = 17.93 m
<h3>Further explanation</h3>
Given
6.00 L water with 6.00 L of ethylene glycol(ρ=1.1132 g/cm³= 1.1132 kg/L)
Required
The molality
Solution
molality = mol of solute/ 1 kg solvent
mol of solute = mol of ethylene glycol
- mass of ethylene glycol :
= volume x density
= 6 L x 1.1132 kg/L
= 6.6792 kg
= 6679.2 g
- mol of ethylene glycol (MW=62.07 g/mol)
=mass : MW
=6679.2 : 62.07
=107.608
6 L water = 6 kg water(ρ= 1 kg/L)
Answer:
It does not matter where the sample of water came from or how it was prepared. Its composition, like that of every other compound, is fixed.
metal rusting in salt water
Which best compares 1 mol of sodium chloride to 1 mol of aluminum chloride?
A. Both have the same molar mass.
B. Both have the same number of ions.
C. Both are made up of 6.02 mc014-1 1023 molecules.
D. Both are made up of 6.02 mc014-2 1023 formula units.
The correct answer on E.D.G is ---Both are made up of 6.02 mc014-2 1023 formula units. D
Electron has the smallest mass
