Since they can still be unstable...nuetral atoms have the same amount of protons to electrons but to be stable they need to fill up there outer shell by gaining or losing electrons
1. Curiosity-They love to learn 2. Open-mindedness- he accepts criticisms fairly well
3. Rationality- he does not believe in superstitions and think that everything has a scientific explanation
4. Critical Mindedness & Correct Judgement- he does not easily jump to conclusions but tries to verify his results by (if possible) repeating the experiment
5. Intellectual Honesty- does not alter his observations and writes the correct observations he has seen
6. Objectivity-<span> he writes accurate results
Hope This Helped :D</span>
Answer:
At the cathode during the electrolysis of an aqueous solution of magnesium iodide, MgI2 , 2I−(aq) is produced
Explanation:
At cathode, reduction reaction takes place.
The dissociation of MgI2 in aqueous solution is Mg2+(aq) and 2I−(aq)
Here, the Iodine reduces to 2I−(aq) from state of 0 (MgI2) to state of -1 (2I−(aq))
Hence, at the cathode during the electrolysis of an aqueous solution of magnesium iodide, MgI2 , 2I−(aq) is produced
We have to know which two substances are related correctly.
The correct answer is: (C) H₃O⁺ is the conjugate acid of H₂O.
In an acid-base reaction, an acid reacts with a base and gives a conjugate base and conjugate acid. The reaction is shown below:
Acid₁ + Base₂ ⇄ Conjugate Base₁ + Conjugate Acid₂
In the reaction H₂CO₃ + H₂O ⇌ H₃O⁺ + HCO₃⁻, H₂CO₃ is an acid because it releases H⁺ ion and converts to HCO₃⁻. Here HCO₃⁻ is the conjugate base of H₂CO₃ ( according Arrhenius theory).
H₂O accepts H⁺ ion and is converted to H₃O⁺ , thus H₂O behaves as Bronsted base. So, H₃O⁺ is the conjugate acid of Bronsted base H₂O.
Hence, the correct answer is: (C) H₃O⁺ is the conjugate acid of H₂O.
