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defon
3 years ago
8

How many liters of radon gas would be in 3.43 moles at standard temperature and pressure (273 K and 100 kPa)?

Chemistry
1 answer:
MissTica3 years ago
5 0

Answer: Option B. 76.83L

Explanation:

1 mole of a gas occupy 22.4L at stp. This implies that 1mole of Radon also occupy 22.4L at stp.

If 1 mole of Radon = 22.4L

Therefore, 3.43 moles of Radon = 3.43 x 22.4 = 76.83L

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Which of the following has the largest number of molecules? a 1 g of benzene, C6H6 b 1 g of formaldehyde, CH2O c 1 g of TNT, C7H
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Answer: 1g of formaldehyde

Explanation:

Molar Mass of benzene (C6H6) = (12x6) + (6x1) = 78g/mol

1mole(78g) of benzene contains 6.02x10^23 molecules.

1g of benzene with contain = (6.02x10^23) /78 = 7.72x10^21 molecules

Molar Mass of formaldehyde (CH2O) = 12 +2+16 = 30g/mol

1mole (30g) of formaldehyde contains 6.02x10^23 molecules.

1g of formaldehyde will contain = (6.02x10^23) /30 = 2.01x10^22 molecules

Molar Mass of TNT(C7H5N3O6) = (12x7)+(5x1)+(14x3)+(16x6) = 227g/mol

1mole(227g) of TNT contains 6.02x10^23 molecules.

1g of TNT will contain = (6.02x10^23)/227 = 2.65x10^21 molecules

Molar Mass of naphthalene (C10H8) = (12x10) +8 =128g/mol

1mole(128g) of naphthalene contains 6.02x10^23 molecules.

1g of naphthalene will contain = (6.02x10^23)/128 = 4.7x10^21 molecules

Molar Mass of glucose(C6H12O6) = (12x6) + 12 +(16x6) = 180g/mol

1mole(180g) of glucose contains 6.02x10^23 molecules.

1g of glucose will contain = (6.02x10^23)/180 = 3.34x10^21 molecules

Therefore, 1g of each of the compound contains the following:

Benzene = 7.72x10^21 molecules

Formaldehyde = 2.01x10^22 molecules

TNT = 2.65x10^21 molecules

Naphthalene = 4.7x10^21 molecules

Glucose = 3.34x10^21 molecules

From the above, we see clearly that formaldehyde has the largest number of molecules

3 0
3 years ago
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