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insens350 [35]
1 year ago
5

what is the name of n2cl4? explain how you determined the bond type and the steps you used to determine the naming convention fo

r the compound. source stylesformatfontsize
Chemistry
1 answer:
scZoUnD [109]1 year ago
5 0

N2Cl4 is known as dinitrogen tetrachloride. Covalent bonds are the sort of bond between species.

Dinitrogen Tetra chloride is the name of the given chemical, N2Cl4. Nitrogen and chlorine are non-metallic elements in this combination. Since nonmetals are electronegative elements, they seek electrons. The octet rule states that an atom must have 8 electrons in its outermost shell. This can be accomplished via sharing or transferring electrons.

Both nitrogen and chlorine are electronegative elements that are seeking an electron to complete their octet. The sharing of one electron will allow the atom to complete its octet. thus creating a covalent connection.

The core atom consists of two nitrogen atoms, and each nitrogen atom is bonded to two chlorine atoms by a covalent bond.

Dinitrogen is created by adding two nitrogen atoms ( Di for two)Tetrachloride, or four chlorine (tetra for 4 )

Dinitrogen tetrachloride (N2Cl4)

To learn more about covalent bonds, visit brainly.com/question/3447218

#SPJ54

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Answer:

0.11mole

Explanation:

Let us assume that the condition is at standard temperature and pressure(STP);

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       Number of moles found in this volume of water  = ?

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The number of moles of water found is  0.11mole

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Explanation:

Molarity is defined as number of moles per liter of solution.

Mathematically,         molarity = \frac{no. of moles}{Volume (in L) of solution}

It is given that molarity is 0.0800 M and volume is 50.00 mL or 0.05 L.

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Therefore, molar mass of cupric sulfate pentahydrate is 249.68 g/mol. So, calculate the mass as follows.

                No. of moles = \frac{mass in grams}{molar mass}

             mass in grams = no. of moles \times molar mass of CuSO_{4}.5H_{2}O

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Thus, we can conclude that 399.488 g of cupric sulfate pentahydrate are needed to prepare 50.00 mL of 0.0800M CuSO4× 5H2O.

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