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Aleksandr [31]
3 years ago
11

Be sure to use proper significant figures. The molecular weight of NaCl is 58.44 grams/mole. To prepare a 0.50 M solution: You w

ould need to have grams of NaCl in 1,000 mL of water.\
Chemistry
2 answers:
Misha Larkins [42]3 years ago
5 0
Your answer would be,
Molarity = moles of solute/volume of solution we needed, 29.22(g)(mol) of NaCI

= 29.22(g)/58.44(g)(mol^-1)(1)/1(L)
= 0.500(mol)(L^-1)



Hope that helps!!!
Mice21 [21]3 years ago
4 0
The answer to the question is 29.22
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Ions that are present before and after a neutralization reaction are
VikaD [51]

Answer:

spectator ions

Explanation:

8 0
4 years ago
At 500 K in the presence of a copper surface , ethanoldecomposes according to the equation
klio [65]

Answer:

Explanation:

rate of reaction

= -ve change in pressure of ethanol / time

= - (250 -237 )/100 = - 13 / 100 torr/s

= - 0.13 torr/s

next

- (237 - 224 )/100 = - 13 / 100 torr/s

= - .13 torr/s

next

- (224 - 211 )/100 = - 13 / 100 torr/s

= - .13 torr/s

so on

So rate of reaction is constant and it does not depend upon concentration or pressure of reactant .

So order of reaction is zero.

rate of reaction =K  [C₂H₅OH]⁰

K is rate constant

K = .13 torr/s

In 900 s decrease in pressure

= 900 x .13 = 117

So after 900s , pressure of ethanol will be

250 - 117 = 133 torr

8 0
3 years ago
1. Una onda tiene una longitud de onda de 2 metros y una frecuencia de 1.5 Hz. ¿Cuál es su velocidad?
IrinaVladis [17]

Answer:

3 m/s

Explanation:

▲

usando la fórmula velocidad = frecuencia multiplicada por la longitud de onda.

v = (1.5)(2)

v= 3 m/s

6 0
3 years ago
Free Energy
ratelena [41]

Answer:

a) galvanic cell

b)electrolytic cell

c) i) K=6.27x10'34

ΔG°=198790 J

ii) K=3.58x10'-34

ΔG°= 191070 J

d) E°=0.278 v

ΔG°= -26827 J

Explanation:

a) There are two kinds of an electrochemical cell, the first is called "galvanic cells", and the second "electrolytic cell".

The fuel cells are capable of produce electric energy through chemical reactions. These reactions are often spontaneous. So, the galvanic cell has a negative value for Gibbs free energy.

b) The electrolytic cell increases the value of Gibbs energy, to positive values, due to the reactions are not spontaneous.

c) i) look image attached

ii) k = look image attached

ΔG° = -nFE° = - 6 X 95500 J/vmole x (-0.33 v)

ΔG° =-191070

d) E°= 0.0592 v/n x lg K

E°= 0.0592V / 1 X log 5.0X10'4

E°= 0.278 v

ΔG° = -nFE° = -1 x 96500 J/ vmole x 0.278v

ΔG° = -26827 J

5 0
3 years ago
How many moles of aluminum oxide would form if 12.5 moles of aluminum burned​
jarptica [38.1K]
<h3>Al + O2 -> Al2O3</h3>

Balance it:

<h3>2Al + 3O2 -> 2Al2O3</h3><h3 />

So you need 2 Al and 3 O2 to make 2 Al2O3 (aluminum oxide).

I'm going to assume you have all the O2 you need.

Since 2 mols of Al is needed to make 2 mols of the product, it's a 1:1 ratio. You get as much aluminum oxide for as much aluminum you burn.

So 12.5 mols if there is not a lack of the O2.

7 0
3 years ago
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