The satellite is 8.02 × 10⁵ m above Earth's surface.
Let H be the height above the surface of the Earth; since we know that the satellite is rotating around the Earth due to the gravitational pull of the planet, we may assert
Procedure to solve:
F = mv²/R+H
H = mv²/F - R
H = (1160 × 7446²/8955 - 6.38 × 10⁶)
M = 8.02 × 10⁵ m
About centripetal force:
The force applied to an item that is in velocity of curved motion that is pointed toward the axis of rotation or the centre of curvature is known as a centripetal force.
The centripetal force formula is given as the product of mass (in kg) and tangential velocity (in meters per second) squared, divided by the radius (in meters) that implies that on doubling the tangential velocity, the centripetal force will be quadrupled. Mathematically it is written as:
F = mv²/r
Learn more about velocity here:
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Answer:
(a) 
(b) 
Explanation:
Given data
The angular velocity of two cylinders ω=257 rad/s
The mass of the two cylinders m=2.88 kg
The radius of small cylinder r₁=0.319 m
The radius of larger cylinder r₂=0.605 m
For Part (a)
The rotational kinetic energy of the cylinder is given by:

Where I is rotational of inertia of solid cylinder about its central axis.
So

Substitute the given values
So

For Part (b)

Substitute the given values

Answer:
Current = 0.063 Amperes
Explanation:
Let the three resistors be R1, R2, and R3 respectively.
Given the following data;
R1 = 25.0Ω,
R2 = 30.0Ω
R3 = 40.0Ω
Voltage = 6 Volts
First of all, we would determine the equivalent or total resistance;
Total resistance (in series) = R1 + R2 + R3
Total resistance = 25.0Ω + 30.0Ω + 40.0Ω
Total resistance = 95 Ω
Next, we find the current flowing through the circuit;
Voltage = current * resistance
Substituting into the formula, we have;
6 = current * 95
Current = 6/95
Current = 0.063 Amperes
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