Answer:
v = 14.32 m/s
Explanation:
According to the principle of conservation of linear momentum, both the momentum and kinetic energy of the system are conserved. Since the two balls are in the same direction of motion before collision, then;
+
= (
+
) v
0.035 × 12 + 0.120 × 15 = (0.035 + 0.120) v
0.420 + 1.800 = (0.155) v
2.22 = 0.155 v
⇒ v =
= 14.323
The velocity of the balls after collision is 14.32 m/s.
The momentum of the ball when it hits the ground is 4.89 kg.m/s.
The given parameters;
The final velocity of the ball when it hits the ground is calculated as follows;
The momentum of the ball when it hits the ground is calculated as follows;
P = mv
P = 0.145 x 33.72
P = 4.89 kg.m/s
Thus, the momentum of the ball when it hits the ground is 4.89 kg.m/s.
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Answer:
(a) 120 eV
(b) 12.840 keV
(c) 0.466%
Solution:
As per the question:
The potential difference between the dees, V = 120 V
No. of passes, n = 107
Now,
(a) The potential energy can be given as 'qV' but by the principle of conservation of energy, this energy with each pass is converted into the kinetic energy of the particle which is given as 120 eV
Thus
The increase in Kinetic energy,
(b) Kinetic energy on completion of 107 passes is given by:
(c) The velocity of the particle can be calculated from its kinetic energy:
Thus
Thus radius can be given as:
where
B = Magnetic field
= mass of proton
Therefore, we can write that:
Thus the percentage increase in radius from n = 107 to n = 108 is given by:
= 0.466 %
Answer:
The expression is Vmem = ΔV - I*Rax
Explanation:
According to the picture, if switch S is closed, the Cmem will be short. If Vcap = 0, the current flows through the capacitor only (not through Rmem), thus Vmem = 0 after closing S.
When C is fully charged, then we have:
Vmem = ΔV - I*Rax
Answer:
Coulomb's law is:
First, force has units of Newtons, the charges have units of Coulombs, and r, the distance, has units of meters, then, working only with the units we have:
N = (1/{e0})*C^2/m^2
then we have:
{e0} = C^2/(m^2*N)
And we know that N = kg*m/s^2
then the dimensions of e0 are:
{e0} = C^2*s^2/(m^3)
(current square per time square over cubed distance)
And knowing that a Faraday is:
F = C^2*S^2/m^2
The units of e0 are:
{e0} = F/m.