Answer:
a
b
Explanation:
From the question we are told that
The height of the helicopter is
The height of the bed of the truck is
The speed of the truck is
Generally the distance between the truck bed and the helicopter is mathematically represented as
=>
=>
Converting to meters
Generally the time at which the helicopter should drop the package is mathematically represented as
Generally distance of the helicopter from the drop site at time t = 0 s is
=>
=>
Answer:
a) t= 0.515 s
b) vf= 5.047 m/s
Explanation:
Because ball move with uniformly accelerated movement we apply the following formulas:
d= v₀t+ (1/2)*g*t² Formula (1)
vf= v₀+gt Formula (2)
Where:
d:displacement in meters (m)
t : time in seconds (s)
v₀: initial speed in m/s
vf: final speed in m/s
g: acceleration due to gravity in m/s²
Known data
v₀=0
d= 1.30 m
g= 9.8 m/s²
Problem development
a) We appy the formula 1 to calculate the time (t):
d= v₀t+ (1/2)*g*t²
1.30= 0+ (1/2)* (9.8)*t²
1.30=4.9*t²
t²=1.30/4.9
t= 0.515 s
b) We appy the formula 2 to calculate the final speed (vf):
vf= v₀+gt
vf= 0+(9.8)*(0.515)
vf= 5.047 m/s
