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monitta
3 years ago
12

A voltage of 75 V is placed across a 150 Ω resistor. What is the current through the resistor?

Physics
1 answer:
Naddika [18.5K]3 years ago
6 0

Answer:

0.5 A

Explanation:

Applying,

V = IR.................. Equation 1

Where V = Voltage, I = current, R = Resistance.

make I the subject of the equation

I = V/R............... Equation 2

From the question,

Given: V = 75 V, R = 150 Ω

Substitute these values into equation 2

I = 75/150

I = 0.5 A.

Hence the cuurent through the resistor is 0.5 A

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An object of mass 25 kg acted upon by a net force of 10 N will experience an acceleration of?
Zolol [24]

Answer:

0.4 m/s2

Explanation:

mass: 25kg

net force: 10 N

acceleration: ?

net force ÷ by mass= acceleration

10 N ÷ 25 Kg = 0.4 m/s2

6 0
2 years ago
A pendulum is constructed from a 6 kg mass attached to a strong cord of length 1.7 m also attached to a ceiling. Originally hang
valina [46]

Answer:

work done is -2.8  × 10⁻⁶ J

Explanation:

Given the data in the question;

mass of the pendulum m = 6 kg

Length of core = 1.7 m

Now, case1, mass is pulled aside a small distance of 7.6 cm and released from rest. so let θ₁ be the angle made by mass with vertical axis.

so, θ₁ = ( 7.6 × 10⁻² m / 1.7 m ) = 0.045 rad

In case2, mass is pulled aside a small distance of 8 cm and released from rest. so let θ₁ be the angle made by mass with vertical axis.

so, θ₂ = ( 8 × 10⁻² m / 1.7 m ) = 0.047 rad.

Now, the required work done will be;

W = \int\limits^{\theta_2} _{\theta_1} {r} \, d\theta

W = \int\limits^{\theta_2} _{\theta_1} {-mgl sin\theta } \, d\theta

W = -mgl  \int\limits^{0.047 } _{0.045 } {sin\theta } \, d\theta

W = -mgl[ -cosθ ]^{0.047}_{0.045 }

W = 6 × 9.8 × 1.7 × [ cos( 0.047 ) - cos( 0.045 ) ]

W = 6 × 9.8 × 1.7 × [ -2.8 × 10⁻⁸ ]

W = -2.8  × 10⁻⁶ J

Therefore, work done is -2.8  × 10⁻⁶ J

6 0
3 years ago
Dx= 7.14m and Dy = -7.55m<br> What is the direction and magnitude of the vector
KengaRu [80]

The Magnitude of the Vector is 10.39m and the direction of the vector is - 46.7°.

<u>Explanation:</u>

GIven dx=7.14m and dy= -7.55m,

The Magnitude of the Vector=\sqrt{dy^{2} +dx^{2} }

Magnitude d= \sqrt{(7.14)^{2} +(-7.55)^{2} } .

                  d=\sqrt{50.97+57}

                  d=\sqrt{107.98}

                  d= 10.39m.

Direction Ф = tan^{-1}\frac{dy}{dx}

                      =tan^{-1} \frac{-7.55}{7.14}      

                      = tan^{-1}(-1.06)

                Ф    = - 46.7°.

5 0
3 years ago
The total thermal energy needed to raise the temperature of this ice cube to 0.0 °C and completely melt the ice cube is 5848 J
USPshnik [31]

Answer:

0.018kg

Explanation:

Q=mlf

m=?,Lf=334000J/kg,Q=5848J

5848=mx334000

5848=334000m

divide both sides by 334000

334000m/334000=5848/334000

m=0.018kg

4 0
3 years ago
If a person runs 68m in 8s, what is his speed?
Bumek [7]

Answer:

19.01396 mph.

Explanation:

4 0
3 years ago
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