A1=2
a2=-8
a3=32
a4=-128
a2/a1=(-8)/2→a2/a1=-4
a3/a2=32/(-8)→a3/a2=-4
a4/a3=(-128)/32→a4/a3=-4
a2/a1=a3/a2=a4/a3=r=-4
an=a1*r^(n-1)
an=2*(-4)^(n-1)
The explicit rule for the nth term of the given sequence is an=2*(-4)^(n-1)
Answer:

Step-by-step explanation:
A quick review on PEMDAS, the order of how to solve an equation:
P - parentheses. When parentheses are being used, you have to do everything inside them before doing everything outside of them.
E - exponents. We'll skip these, since there aren't any exponents we need to worry about in this equation.
M/D - multiplication/division. I include these both together because they can be done at the same time.
A/S = addition/subtraction. Can also be done at the same time.
Some other things to note:
You add all the things with an x attached to it, and you add all the things without an x attached to it, and these never cross.
When you bring something from one side of an equal sign to another, you make it negative.
Let's solve for x using what we've learned:

Answer:
8mph
Step-by-step explanation:
when dina arrived to 20 masha was at 16. so the relation is 20/16 and if dina's speed was 10 your formula is 10/x=20/16 that means x/10=16/20. so x will be 8
A. 5x - 6 ................